The percentage decline in the production of fertilizers from 1997 to 1998 is

Solution

Production of fertilizers in 1997 (in 10,000 tonnes) = 60

Production of fertilizers in 1998 (in 10,000 tonnes) = 45

=> Percentage decline = $$\frac{(60-45)}{60}\times100$$

= $$\frac{1}{4}\times100=25\%$$

=> Ans - (B)

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