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Question 112
The numerical value of
$$\frac{9}{cosec^{2}\theta}\ + 4\ cos^{2}\theta +\ \frac{5}{1+tan^{2}\theta}$$
Solution
Expression : $$\frac{9}{cosec^{2}\theta}\ + 4\ cos^{2}\theta +\ \frac{5}{1+tan^{2}\theta}$$
=Â $$9sin^2\theta + 4\ cos^{2}\theta + \frac{5}{sec^2\theta}$$
=Â $$9sin^2\theta + 4\ cos^{2}\theta + 5cos^2\theta$$
= $$9sin^2\theta+9cos^2\theta$$
= $$9(sin^2\theta+cos^2\theta)=9$$
=> Ans - (B)
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