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If $$\tan 22 \frac{1}{2} = x$$, then the value of $$\cos 67 \frac{1^\circ}{2}$$ is
$$\frac{x}{\sqrt{x^2 + 1}}$$
$$\frac{1}{\sqrt{x^2 + 1}}$$
$$\frac{x}{\sqrt{x^2 - 1}}$$
$$\frac{1}{\sqrt{x^2 - 1}}$$
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