If 12 boys or 15 girls can do a work in 48 days, in what time will 24 boys and 6 girls do twice the work?
12 boys or 15 girls can do a work in 48 days
=> $$12 boys \equiv 15 girls$$
=> $$24 boys \equiv 30 girls$$
We need to find for 24 boys and 6 girls. Substituting value of 24 boys
=> $$24 boys + 6 girls = 36 girls$$
Now, using : $$\frac{M_1 \times D_1}{W_1} = \frac{M_2 \times D_2}{W_2}$$
=> $$\frac{15 \times 48}{1} = \frac{36 \times D_2}{2}$$
=> $$15 \times 48 = 18 \times D_2$$
=> $$D_2 = \frac{15 \times 48}{18}$$
=> $$D_2 = 5 \times 8 = 40$$ days
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