Question 111

The liSt price of an article is 160 and a customer buys it for 122.40 after two successive discounts. If the first discount is 10%, then second discount is

Solution

Marked price = 160

After 1st discount of 10% => 10% of 160 = $$\frac{10}{100}$$ * 160 = 16

Amount payable = 160 - 16 = 144

Let 2nd discount = $$x$$%

After 2nd discount of $$x$$%

=> $$x$$% of 144 = $$\frac{x}{100} * 144 = 1.44x$$

=> Customer will pay = 144 - $$1.44x$$ = 122.40

=> $$1.44x$$ = 21.6

=> $$x$$ = 15

Create a FREE account and get: