Question 111

If (5x^2 - 3y^2): xy = 11:2, and x,y are positive, then the value of x/y is:

Solution

it is given that (5x^2 - 3y^2): xy = 11:2

let divide the numerator and denominator of left hand side of the given equation by y^2

we will get ,

$$\frac{5( \frac{x}{y})^2 - 3}{\frac{x}{y}}$$ = $$\frac{11}{2}$$

let $$\frac{x}{y}$$ = k

So, $$\frac{5k^2-3}{k}$$ = $$\frac{11}{2}$$

Solving this we get , k = $$\frac{3}{2}$$

hence $$\frac{x}{y}$$ = $$\frac{3}{2}$$

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