Question 110
A jar contains a mixture of two liquids A and B in the ratio 4 : 1. When 10 litre of the mixture is replaced with liquid B, the ratio becomes 2 : 3. The volume of liquid A present in the jar earlier was:
Solution
$$\frac{QNR}{total} = \frac{QNR(initial)}{total} (1- \frac{\textrm{Replaced Quantity}}{total})$$
QNR is the quantity which has not entered again
so here QNR is A
$$\frac{2x}{5x} = \frac{4x}{5x} (1- \frac{10}{5x})$$
Upon solving $$x=4$$
So, volume of A present in the jar earlier was = $$4x=4\times\ 4=16$$ litres
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