Question 110

If $$\sqrt{1+\frac{x}{961}} = \frac{32}{31}$$, then the value of x is

Solution

we need to find value of x and it is given to us that $$\sqrt{1+\frac{x}{961}} = \frac{32}{31}$$

$$\frac{32}{31}$$ = $$\sqrt{\frac{1024}{961}}$$

hence ,

$$\sqrt{1+\frac{x}{961}}$$ = $$\sqrt{\frac{1024}{961}}$$ = $$\sqrt{1 + \frac{63}{961}}$$

hence x = 63

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