Question 110

If $$(\frac{3}{5})^3(\frac{3}{5})$$-6 = $$(\frac{3}{5})$$2x-1 then x is equal to

Solution

$$(\frac{3}{5})^3(\frac{3}{5})$$-6 = $$(\frac{3}{5})$$2x-1
we know that aman = am+n
$$(\frac{3}{5})^3(\frac{3}{5})$$-6 = $$(\frac{3}{5})$$3-6 = $$(\frac{3}{5})$$-3
So now
-3 = 2x-1
2x = -2
x = -1

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If $$(\frac{3}{5})^3(\frac{3}{5})$$-6 = $$(\frac{3}{5})$$2x-1 then x is equal to

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