Nine years later, age of B will be equal to the present age of A. Sum of A's age 3 years later and B's age 4 years ago is 76. If C is half of the present age of B, then what will be C's age (in years) after 10 years?
Let A's present age = $$x$$ years
=> B's present age = $$(x-9)$$ years
According to ques,
=> $$(x+3)+(x-9-4)=76$$
=> $$2x-10=76$$
=> $$2x=76+10=86$$
=> $$x=\frac{86}{2}=43$$
Thus, B's present age = $$43-9 = 34$$
=> C's present age = $$\frac{34}{2}=17$$ years
$$\therefore$$ C's age after 10 years = $$17+10=27$$ years
=> Ans - (C)
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