Question 11

Nine years later, age of B will be equal to the present age of A. Sum of A's age 3 years later and B's age 4 years ago is 76. If C is half of the present age of B, then what will be C's age (in years) after 10 years?

Solution

Let A's present age = $$x$$ years

=> B's present age = $$(x-9)$$ years

According to ques,

=> $$(x+3)+(x-9-4)=76$$

=> $$2x-10=76$$

=> $$2x=76+10=86$$

=> $$x=\frac{86}{2}=43$$

Thus, B's present age = $$43-9 = 34$$

=> C's present age = $$\frac{34}{2}=17$$ years

$$\therefore$$ C's age after 10 years = $$17+10=27$$ years

=> Ans - (C)

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