Question 109

What is the value of (x) in the following equation ?

$$ \frac { x ^ {1.2}}{98} = \frac {28}{x^{1.8}}$$

Solution

The question can be reframed as,

$$x^{1.2}\times x^{1.8}$$ = 98*28 = 14*7*7*4= 7*7*7*8

x^3=7*7*7*8

Hence, x = 7*2 = 14

 


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