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Twelve people are sitting in two parallel rows containing six people each, in such a way that there is an equal distance between adjacent persons. In row-1 P, Q, R, S, T and V are seated and all of them are facing South. In row-2 A, B, C, D, E and F are seated and all of them are facing North. Therefore, in the given seating arrangement each member seated in a row faces another member of the other row.
S sits third to right of Q. Either S or Q sits at an extreme end of the line. The one who faces Q sits second to right of E. Two people sit between B and F. Neither B nor F sits at an extreme end of the line. The immediate neighbour of B faces the person who sits third to the left of P. R and T are immediate neighbours of each other. C sits second to the left of A. T does not face the immediate neighbour of D.
Lets number the boxes from 1 to 12 as shown below to discuss the positions of the 12 people. S sits third to the right of Q and either of them sits at an extreme end. This is possible in 2 ways.
Case 1) Sits in 1 and Q in 4
Case 2) S sits in 3 and Q in 6
In Case 1, E sits in box 8. Now, there are 2 people sit between B and F and neither B nor F sit at the extreme end. That is not a possibility.
So, we proceed with case 2.
So, we can confirm that S sits in 3, Q sits in 6 and E sits in 10.
Positions of B and F create 2 cases.
Case 3) B sits in 8 and F sits in 11
Case 4) B sits in 11 and F sits in 8
Case 3 is impossible because the immediate neighbor of B faces the person who sits third to the left of P. Even if P is sitting in 1, The immediate neighbor of B has to face 4.
That is only possible if B is in 11 and P is in 1 or 3. Since S is already in 3, P should be in 1.
C sits second to the left of A. So, C is in 7 and A is in 9. D is therefore in 12.
R and T are immediate neighbors of each other. So, they should be in 4 and 5.
T doesn't face the immediate neighbor of D. So, T is in 4 and R is in 5. So, 2 is V.
The diagram therefore is as shown below:
That answers the question.
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