Question 109

30 men can do a piece of work in 16 days. How many men would be required to do the same work in 20 days ?

Solution

Using : $$M_1 D_1 = M_2 D_2$$

30 men can do a piece of work in 16 days

=> $$M_1 = 30 , D_1 = 16$$ and $$D_2 = 20$$

Let $$M_2$$ men finish the same work in 20 days

=> $$30 \times 16 = M_2 \times 20$$

=> $$M_2 = \frac{480}{20} = 24$$

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