Join WhatsApp Icon CAT WhatsApp Group
Question 108

The value of $$\frac{(3.2)^3 - 0.008}{(3.2)^2 + 0.64 + 0.04}$$ is

we know that $${a^3 - b^3 = (a-b)(a^2 + b^2 + ab)}$$

$$\frac{(3.2)^3 - 0.008}{(3.2)^2 + 0.64 + 0.04}$$

= $$\frac{(3.2)^3 - (0.2)^3}{(3.2)^2 + 0.2 x 3.2 + (0.2)^2}$$

= 3.2 -0.2 (using the abive mentioned theorem)

= 3

Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free