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Solution
$$121a^{2}+64b^{2}$$
= $$(11a)^{2} + (8b)^{2}$$
$$\because (x+y)^{2} = x^{2} + y^{2} + 2xy$$
$$\therefore$$ Required expression = $$2 * 11a * 8b$$
= $$176ab$$
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