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A spherical ball, when immersed in a cylinder of base radius 7 cms., raises the level of water in the cylinder by 2 cms. Then the radius of the ball (in cm)
$$\sqrt[3]{\frac{210}{6}}$$
$$\sqrt[3]{\frac{147}{2}}$$
$$\frac{\sqrt{94}}{7}$$
$${\frac{\sqrt{95}}{3}}$$
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