Question 105
A dealer has 1000 kg sugar and he sells a part of it at 8% profit and the rest of it at 18% profit. The overall profit he earns is 14%. What is the quantity which is sold at 18% profit ?
Solution
Let the cost price be 100x.
Let the part sold at 8% profit be K kg. So, part sold at 18% profit would be (1000-K) kg
Total profit = $$\ \frac{\ SP\ -\ CP}{CP}\times\ 100$$ = $$\ \frac{\ 108x\times K\ +\ 118x\left(1000-K\right)\ \ -\ 1000\times\ 100x}{1000\times\ 100x}\times\ 100$$ = 14
On solving it, we get K=400kg.
Quantity sold at 18% profit = 1000-K = 600 Kg.
So, option E is the answer.
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