Question 104

The last digit of the number obtained by multiplying the numbers $$81 \times 82 \times 83 \times 84 \times 85 \times 86 \times 87 \times 88 \times 89$$ will be

To get the last digit, we could simply find the product of last digits of all the numbers i.e. 1*2*3*4*5*6*7*8*9.
As, there is 5 and 2 in the multiplication, 10 becomes a factor of the product and thus last digit will surely be 0.

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