Question 104

AB and CD are two parallel chords drawn on two opposite sides of their parallel diameter such that AB = 6 cm, CD = 8 cm. If the radius of the circle is 5 cm, the distance between the chords, in cm, is

Solution

OE $$\perp$$ CD => DE = 4 cm

Similarly, BF = 3 cm

From $$\triangle$$ODE

=> $$OE = \sqrt{(OD)^2 - (DE)^2}$$

=> $$OE = \sqrt{5^2 - 4^2} = \sqrt{9} = 3$$ cm

Similarly, OF = 4 cm

$$\therefore$$ EF = OE + OF = 3 + 4 = 7 cm

View More Questions From Geometry

Create a FREE account and get: