Question 103
Given that ∠ABC = 90°, BC is parallel to DE. If AB = 12, BD = 6 and BC = 10, then the length of DE is
Solution
BC | | DE
=> $$\angle$$ABC = $$\angle$$ADE = 90
and $$\angle$$ACB = $$\angle$$AED
$$\therefore$$ $$\triangle$$ABC $$\sim$$ $$\triangle$$ADE
=> $$\frac{AB}{AD} = \frac{BC}{DE}$$
=> $$\frac{12}{18} = \frac{10}{DE}$$
=> $$DE = 15$$ cm
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