Question 103

The price of 8 books and 24 registers is Rs. 1760. If the price of one book is Rs. 124 more than the price of one register, what is the total price of 4 books and 2 registers ? (In Rs.)

Solution

Let price of 1 register = $$Rs. x$$

=> Price of book = $$Rs. (x + 124)$$

Acc. to ques, => $$8 (x + 124) + 24x = 1760$$

=> $$8x + 992 + 24x = 1760$$

=> $$32x = 1760 - 992 = 768$$

=> $$x = \frac{768}{32} = 24$$

Thus, price of book = $$24 + 124 = 148$$

$$\therefore$$ Total price of 4 books and 2 registers

= $$(4 \times 148) + (2 \times 24)$$

= $$592 + 48 = Rs. 640$$

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