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Solution
$$2sin^2 θ$$ $$ =2 \times (1-cos^2 θ) $$
$$2sin^2 θ + 3cos^2 θ$$ $$= 2- 2 cos^2θ + 3 cos^2θ= 2+cos^2 θ$$
The least value of $$cos^2 θ$$ is $$0$$.
Hence the least value is $$2$$.
Hence Option D is the correct answer.
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