If $$x = \left(\frac{3}{2}\right)^{2} \left(\frac{2}{3}\right)^{-4}$$, the value of $$x^{-2}$$ is

A

$$\left(\frac{2}{3}\right)^{12}$$

B

$$\left(\frac{3}{2}\right)^{12}$$

C

$$\left(\frac{6}{5}\right)^{-12}$$

D

$$\left(\frac{5}{6}\right)^{-12}$$