Solution
Given : $$a=1+\sqrt{3}$$
Squaring both sides, => $$a^2=(1+\sqrt3)^2$$
=> $$a^2=1+3+2\sqrt3=4+2\sqrt3$$ ---------(i)
Similarly, $$b^2=4-2\sqrt3$$ ----------(ii)
Adding equation (i) and (ii), we get :
=> $$(a^2+b^2)=(4+2\sqrt3)+(4-2\sqrt3)=8$$
=> Ans - (B)
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