Solution
Prime numbers from 0 to 100 are 2,3,5,7,11,........
The multiplication will be very complicated. So, the question requires you to find number of zeros at the end.
Product = 2*3*5*7.....
No. of zeros at end = highest power of 10, which is 1 in this case(since 2,5 occur only once each and no higher powers of 2 and 5 occur).
So, the answer is option D as it has only 1 zero at the end.
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