If $$x(3-\frac{2}{x})=\frac{3}{x}$$, then value of $$x^{2}+\frac{1}{x^{2}}$$ is

A

$$1\frac{1}{9}$$

B

$$2\frac{4}{9}$$

C

$$3\frac{5}{9}$$

D

$$4\frac{7}{9}$$