Two charged thin infinite plane sheets of uniform charge density $$\sigma_+$$ and $$\sigma_-$$, where $$|\sigma_+| > |\sigma_-|$$, intersect at the right angle. Which of the following best represents the electric field lines for the system:

$$E_+ = \frac{|\sigma_+|}{2\varepsilon_0}$$

$$E_- = \frac{|\sigma_-|}{2\varepsilon_0}$$

$$|\sigma_+| > |\sigma_-| \implies E_+ > E_-$$

$$\tan\alpha = \frac{E_-}{E_+}$$

$$\tan\alpha < 1 \implies \alpha < 45^\circ$$

The electric field lines must be straight lines within each quadrant, directed away from the positively charged plane ($$\sigma_+$$) and pointing towards the negatively charged plane ($$\sigma_-$$), making a sharper angle with the $$\sigma_+$$ axis than the $$\sigma_-$$ axis.