Three of the following four numbers are alike in a certain way and one is different. Pick the number that is different from the rest.
The logic here is
50 = 49 + 1 = 7$$^2$$ + 1
65 = 64 + 1 = 8$$^2$$ + 1
170 = 169 + 1 = 13$$^2$$ + 1
The above numbers are in the form of n$$^2$$ + 1
195 = 196 - 1 = 14$$^2$$ - 1
It is in the form of n$$^2$$ - 1
$$\therefore\ $$195 is the different number among the given numbers.
Hence, the correct answer is Option C
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