Question 10

Three of the following four numbers are alike in a certain way and one is different. Pick the number that is different from the rest.

Solution

The logic here is

50 = 49 + 1 = 7$$^2$$ + 1

65 = 64 + 1 = 8$$^2$$ + 1

170 = 169 + 1 = 13$$^2$$ + 1

The above numbers are in the form of n$$^2$$ + 1

195 = 196 - 1 = 14$$^2$$ - 1

It is in the form of n$$^2$$ - 1

$$\therefore\ $$195 is the different number among the given numbers.

Hence, the correct answer is Option C

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