CMAT 2020 Question 10

Question 10

The work done by a man, woman and child are in the ratio 3: 2:1. If daily wages of 20 men, 30 women and 36 children amount to 78/-, what will be the wages of 15 men, 21 women and 30 children for 18 weeks ?

Solution

Let the efficiency of a man, woman and child be $$3x,2x,x$$ espectively.

Thus, 1 day wage = $$(3x\times20)+(2x\times30)+(x\times36)=78$$

=> $$156x=78$$

=> $$x=\frac{1}{2}$$

$$\therefore$$ Wages of 15 men, 21 women and 30 children for 18 weeks = $$[(15\times3x)+(21\times2x)+(30\times x)]\times18\times7$$

= $$117\times\frac{1}{2}\times126$$

= $$117\times63=Rs.$$ $$7,371$$

=> Ans - (A)


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