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4 years, 2 months ago
4 years, 2 months ago
Let the rate of reading be S1 and time be t for the first case
Here, S1 * t = 12 (questions)
Now , as the time needs to be cutdown by 10 % , we have a new equation just like the above one as
S2 * 0.9t =12 (S2 = new rate of reading)
Comparing the two equations , we arrive at S2/S1 =10/9 which corresponds to 11.11% increase in the reading speed required
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