Two curves y=x^2-6x+8 and y=-x^2+bx+c are in x-y plane.If maxima of one curve is minima of other curves, then what is the value of b?

Differentiate both equations and equate them to zero.
Curve one: 2x-6=0 i.e. x=6
Curve two: -2x+b=0. For x=6 obtained from above equation, we get b=6

b=0

@Sanjoy, You should be able to solve this problem easily by using the tips given in the CC50 concept. Give it a try.

Sorry the 2nd equation is y=-x^2+bx+c.It's my typing mistake..

Hi Sujoy, as the coefficient of $$x^2$$ in both the equations is positive, both equations will have only minima. Hence for no value of b, the maxima of one curve can be equal to the minima of the other curve.
Please go through our CC50 concept on Maxima and Minima of Quadratic equations.
https://cracku.in/cat/cc50/maxima-minima-quad-equations