[Download PDF] TS ICET 2018 Shift 1 Paper with Solutions

Instructions

For the following questions answer them individually

Question 131

$$(1 + \sqrt{3})^6 + (1 - \sqrt{3})^6 =$$

Video Solution

Question 132

If $$A = \left(\begin{array}{c}0 & 0 & 1\\ 0 & 1 & 0 \\1 & 0 & 0\end{array}\right)$$ and $$B = \left(\begin{array}{c}1 & 0 & 0\\ 0 & 1 & 0 \\0 & 0 & 1\end{array}\right)$$ then $$A^{15}B^{17} + A^{17}B^{15} =$$

Video Solution

Question 133

If a. b, c are three distinct positive real numbers and if

Figure

Video Solution

Question 134

$$\lim_{x \rightarrow 1}\frac{x^2 - 5x + 4}{x^2 - 3x + 2} =$$

Video Solution

Question 135

$$y = \tan^{-1}\left[\frac{1 + \tan x}{1 - \tan x}\right] \Rightarrow \frac{dy}{dx} =$$

Video Solution

Question 136

PQRS is a square with diagonal a + b. The perimeter of the square whose area is twice that of PQRSis

Video Solution

Question 137

In a triangle the point of concurrence ofinternal bisectors of its angles is called its

Video Solution

Question 138

A, B, C, D are four points on a circle AC and BD intersect at E such that $$\angle BEC = 130^\circ$$ and $$\angle ECD = 20^\circ$$. Then $$\angle BAC =$$

Video Solution

Question 139

The area (in sq units) of the triangle formed by the points (1. 2), (3. 4) and the origin is

Video Solution

Question 140

If the points A(1, 2), B(3, -4), C(5, -6) and D(11, -8) lie on a circle, then the center of the circle is

Video Solution

CAT Content

TS ICET 2018 Shift 1

TS ICET 2018 Shift 1

$$(1 + \sqrt{3})^6 + (1 - \sqrt{3})^6 =$$

If $$A = \left(\begin{array}{c}0 & 0 & 1\\ 0 & 1 & 0 \\1 & 0 & 0\end{array}\right)$$ and $$B = \left(\begin{array}{c}1 & 0 & 0\\ 0 & 1 & 0 \\0 & 0 & 1\end{array}\right)$$ then $$A^{15}B^{17} + A^{17}B^{15} =$$

If a. b, c are three distinct positive real numbers and if Figure

$$\lim_{x \rightarrow 1}\frac{x^2 - 5x + 4}{x^2 - 3x + 2} =$$

$$y = \tan^{-1}\left[\frac{1 + \tan x}{1 - \tan x}\right] \Rightarrow \frac{dy}{dx} =$$

PQRS is a square with diagonal a + b. The perimeter of the square whose area is twice that of PQRSis

In a triangle the point of concurrence ofinternal bisectors of its angles is called its

A, B, C, D are four points on a circle AC and BD intersect at E such that $$\angle BEC = 130^\circ$$ and $$\angle ECD = 20^\circ$$. Then $$\angle BAC =$$

The area (in sq units) of the triangle formed by the points (1. 2), (3. 4) and the origin is

If the points A(1, 2), B(3, -4), C(5, -6) and D(11, -8) lie on a circle, then the center of the circle is

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If a. b, c are three distinct positive real numbers and if

Figure