TS ICET 2018 Question Paper Shift-1

Instructions

For the following questions answer them individually

TS ICET 2018 Shift-1 - Question 131


$$(1 + \sqrt{3})^6 + (1 - \sqrt{3})^6 =$$

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TS ICET 2018 Shift-1 - Question 132


If $$A = \left(\begin{array}{c}0 & 0 & 1\\ 0 & 1 & 0 \\1 & 0 & 0\end{array}\right)$$ and $$B = \left(\begin{array}{c}1 & 0 & 0\\ 0 & 1 & 0 \\0 & 0 & 1\end{array}\right)$$ then $$A^{15}B^{17} + A^{17}B^{15} =$$

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TS ICET 2018 Shift-1 - Question 133


If a. b, c are three distinct positive real numbers and if

Figure

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TS ICET 2018 Shift-1 - Question 134


$$\lim_{x \rightarrow 1}\frac{x^2 - 5x + 4}{x^2 - 3x + 2} =$$

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TS ICET 2018 Shift-1 - Question 135


$$y = \tan^{-1}\left[\frac{1 + \tan x}{1 - \tan x}\right] \Rightarrow \frac{dy}{dx} =$$

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TS ICET 2018 Shift-1 - Question 136


PQRS is a square with diagonal a + b. The perimeter of the square whose area is twice that of PQRSis

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TS ICET 2018 Shift-1 - Question 137


In a triangle the point of concurrence ofinternal bisectors of its angles is called its

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TS ICET 2018 Shift-1 - Question 138


A, B, C, D are four points on a circle AC and BD intersect at E such that $$\angle BEC = 130^\circ$$ and $$\angle ECD = 20^\circ$$. Then $$\angle BAC =$$

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TS ICET 2018 Shift-1 - Question 139


The area (in sq units) of the triangle formed by the points (1. 2), (3. 4) and the origin is

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TS ICET 2018 Shift-1 - Question 140


If the points A(1, 2), B(3, -4), C(5, -6) and D(11, -8) lie on a circle, then the center of the circle is

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