[Download PDF] TS ICET 1st Oct 2020 Shift-1 Paper with Solutions

Instructions

For the following questions answer them individually

Question 81

If $$x = \sqrt{3} + \sqrt{2}$$, then $$x^{3} + \frac{1}{x^{3}} =$$

Video Solution

Question 82

The least values of $$x$$ and y, respectively, so that 7$$x$$342y is divisible by 88 are

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Question 83

A natural number m is multiplied by 11 and then 22 is added to the product. The result is a multiple of 17, Then the smallest value of m is

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Question 84

The smallest positive integer which is perfect square and is also divisible by 15, 18 and 24 is

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Question 85

The smallest positive integer which when subtracted from 3000 is divisible by 7, 11 and 13

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Question 86

If 3.8$$\overline{12} = \frac{p}{q}$$ where p, q are positive integers with no common factors, except 1, then 2q + p =

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Question 87

If the reciprocal of the sum of the reciprocals of $$\frac{3}{5},\frac{5}{7},\frac{4}{9}$$ is $$\frac{p}{q}$$ when p, q positive integers with GCD 1, then 3q - 5p =

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Question 88

The biggest number among the following is
$$\sqrt{10} - 3, \sqrt{13} - 2\sqrt{3}, \sqrt{5} - 2, 3 -2\sqrt{2}$$

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Question 89

$$\frac{(1.73)^{2}-(1.73)(1.27)+(1.27)^{2}}{(1.73)^{3} + (1.27)^{3}}$$

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Question 90

If p% of 96 is equal to q% of 21, then $$\frac{1}{3p}$$% of 5q is equal to

Video Solution

CAT Content

TS ICET 1st Oct 2020 Shift-1

If $$x = \sqrt{3} + \sqrt{2}$$, then $$x^{3} + \frac{1}{x^{3}} =$$

The least values of $$x$$ and y, respectively, so that 7$$x$$342y is divisible by 88 are

A natural number m is multiplied by 11 and then 22 is added to the product. The result is a multiple of 17, Then the smallest value of m is

The smallest positive integer which is perfect square and is also divisible by 15, 18 and 24 is

The smallest positive integer which when subtracted from 3000 is divisible by 7, 11 and 13

If 3.8$$\overline{12} = \frac{p}{q}$$ where p, q are positive integers with no common factors, except 1, then 2q + p =

If the reciprocal of the sum of the reciprocals of $$\frac{3}{5},\frac{5}{7},\frac{4}{9}$$ is $$\frac{p}{q}$$ when p, q positive integers with GCD 1, then 3q - 5p =

The biggest number among the following is$$\sqrt{10} - 3, \sqrt{13} - 2\sqrt{3}, \sqrt{5} - 2, 3 -2\sqrt{2}$$

$$\frac{(1.73)^{2}-(1.73)(1.27)+(1.27)^{2}}{(1.73)^{3} + (1.27)^{3}}$$

If p% of 96 is equal to q% of 21, then $$\frac{1}{3p}$$% of 5q is equal to

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The biggest number among the following is
$$\sqrt{10} - 3, \sqrt{13} - 2\sqrt{3}, \sqrt{5} - 2, 3 -2\sqrt{2}$$