SSC MTS 2021 Question Paper Shift 3 (Oct 27th)

Instructions

For the following questions answer them individually

SSC MTS 2021 Shift 3 (Oct 27th) - Question 61


An article is sold At a profit of $$13\frac{1}{4}\%$$ . Had it been sold for ₹76,70 more, the profit would have been $$16\frac{1}{5}\%$$. The cost price of the article is:

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 62


The radius of a cylinder is increased by 20% and its height is decreased by 45%. What is the percentage increase/decrease in the volume of the cylinder?

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 63


The value of $$5 of 8-6+\left[\left(27-3\right)\div6-4\right]$$ is:

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 64


5 men and 6 women can earn ₹10,500 in 6 days. 8 men and 12 women can earn ₹24,800 in 8 days. In how many days will 7 men and 10 women earn ₹26,500?

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 65


When the numerator of a fraction is increased by 25% and the denominator is increased by $$31\frac{1}{4}\%$$, it becomes $$\frac{5}{14}$$. Find the fraction.

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 66


The mean of 70 items was 32. Later, it was discovered that two items were misread as 64 and 28 instead of 46 and 81. The correct mean is:

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 67


The sum of the radius of the base and slant height of a right circular cone is 49 cm. If the total surface area is 1848 $$cm^{2}$$, then its height is:
(Take $$\pi=\frac{22}{7}$$)

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 68


₹86,581 is divided among A and B in the ratio of 9 : 2. The difference between 4 times the share of A and 10 times the share of B is:

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 69


A and B can do a work in 21 days and 14 days, respectively. They started the work by working together, but after 5 days, due to some reasons, B left the work and A completed the remaining work. The whole work was completed in:

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SSC MTS 2021 Shift 3 (Oct 27th) - Question 70


The present ages of a mother and her son are in the ratio of 6 : 1. When the son becomes as old as his mother now, then the ratio of his father's age to his mother's age is 13 : 11. When the son becomes as old as his father now, then the sum of the ages of the father and son will be 115 years. The present age of the father is:

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