SRCC GBO 2009 Question Paper

In common English, government actions are referred to as "Its actions" and not its actions. So, Option B is the correct answer.

Option D is the answer as the correct way to phrase it would be "that" our father is a communist.

In common English, it should be "open the gates" . So, Option C is the correct answer.

The block of the flat should be singular. Therefore, instead of were, we should say was. So, Option C is the correct answer. 

Abridge means to shorten, curtail or abbreviate something

In a textual context, it means abstract- to summarise

It can also mean- to contract, or reduce in size.

It does not mean venerate- venerate means respect. 

If someone is cognizant of something, they are aware of it or understand it. So , Options A, B and D are likely synonyms of the word.

Vindict is having or showing a desire to harm someone because you think that the person has harmed you. So, Option C is the correct answer.

A fissure is a narrow opening or crack of considerable length and depth, usually occurring from some breaking or parting.

Options A, B and C are similar to it. 

Fusion on the other hand means to combine something. Therefore, Option D is the correct answer. 

Innocuous is something that is not harmful or offensive.

Option B, C and D are close to what it means. Option A, immoral on the other hand means something that is not moral.. Therefore, Option A is the correct answer.

Perennial is something lasting or existing for a long or apparently infinite time, enduring or continually recurring.

Option B on the other hand (perishable) means likely to decay or go bad quickly.

Therefore, Option B is the correct answer.

Option D is the correct answer.

The word “latent” means existing but not yet developed or manifest, hidden or concealed. Therefore, the words that are opposite in meaning to “latent” would be:

a) Apparent: Clearly visible or understood; obvious. b) Exposed: Make (something) visible by uncovering it. c) Manifest: Clear or obvious to the eye or mind.

The word that does not fit in this context is:

d) Officious: Assertive of authority in a domineering way, especially with regard to trivial matters.

Therefore, “officious” is the most appropriate choice here as it is not the correct antonym of “latent”. It does not convey the meaning of something being visible or revealed. 

The word “naive” typically means showing a lack of experience, wisdom, or judgment. Therefore, the words that are opposite in meaning to “naive” would be:

a) Crafty: Clever at achieving one’s aims by indirect or deceitful methods. b) Diplomatic: Having the ability to deal with people in a sensitive and effective way. d) Wily: Skilled at gaining an advantage, especially deceitfully.

The word that does not fit in this context is:

c) Brave: Ready to face and endure danger or pain; showing courage.

Therefore, “brave” is the most appropriate choice here as it is not the correct antonym for “naive”. 

Option A is the correct answer.

The word “regal” typically means of, resembling, or fit for a monarch, especially in being magnificent or dignified. Therefore, the words that are opposite in meaning to “regal” would be:

b) Beggarly: Resembling or befitting a beggar; extremely poor. c) Slavish: Showing no originality; blindly imitative. d) Poor: Lacking sufficient money to live at a standard considered comfortable or normal in a society.

The word that does not fit in this context is Option a) Legal: Permitted by law.

Therefore, “legal” is the most appropriate choice here as it is not the correct antonym of “regal”.

Option A is the correct answer.

The word “tranquillity” typically means the quality or state of being tranquil or calm. Therefore, Option A is a synonym of Tranquility.

The other options are antonyms of the word:
b) Excitement: A feeling of great enthusiasm and eagerness. c) Agitation: A state of anxiety or nervous excitement. d) Disturbance: The interruption of a settled and peaceful condition.

The word “amalgamate” means to combine or unite to form one organization or structure. Therefore, the words that are opposite in meaning to “amalgamate” would be:

a) Dissociate: Disconnect or separate (used especially in abstract contexts). b) Unravel: Undo (twisted, knitted, or woven threads). c) Untangle: Free from a tangled or knotted state.

The word that does not fit in this context is:

d) Seethe: (of a person) be filled with intense but unexpressed anger.

Therefore, “seethe” is the most appropriate choice here as it is not the correct antonym of “amalgamate”. It does not convey the meaning of separation or disconnection. Instead, it relates to a state of intense but unexpressed anger.

In this question, “TEPID: HOT”, the relationship between the words is one of degree. “Tepid” means slightly warm, while “hot” refers to a higher degree of warmth.

The pair related in the same way as “TEPID: HOT” is Option B: Pat: Slap. A pat is a light touch, while a slap is a hit with more force, which is similar to the relationship between tepid and hot.

Modesty and Arrogance are opposites of each other.  Modesty is the quality or state of being unassuming in the estimation of one's abilities.

Arrogance, on the other hand, is the quality of being unpleasantly proud and behaving as if you are more important than, or know more than, other people

So, the correct answer would be Option C as it also has words that are opposites of each other. Debility the quality or state of being weak, feeble, or infirm. Strength on the other hand implies strong.

Here, the relation is cause and effect. Germs cause diseases, so we have to find a pair of words that illustrate the same relationship. 

Option D is the correct answer, as Wars cause destruction.

The rest of the options don't exemplify a cause-effect relationship.

Flowers are a part of a bouquet, or flowers make up a bouquet. So, we have to find a pair of words that illustrate the same relation. 

Here, only Option B exemplifies this. Multiple links make a chain. So the correct answer is Option B.

We first identify the relation between the words in the question- encourage: restrict- these are antonyms. 

Now we look at options that may have the same relationship as antonyms. 

Option A- gain: supply is the only antonym pair and hence is correct. 

Option d) “to start making” is the best choice.

 The sentence says it’s time for us to begin or “start” doing something. That something is “making preparation to leave.” So, “to start making” fits perfectly in the blank and makes the sentence sound right.

The other options don’t fit as well because they don’t sound as good in the sentence, or they don’t follow the rules of how we usually use words in English.

Option B is the correct answer.

The completed sentence is: “We better start now to work for our project.”

The term “better” in this context is a modal verb that is often used in informal spoken English. Modal verbs are auxiliary verbs that express necessity or possibility, and in this case, “better” is expressing a strong recommendation or advice.

When we say “We better start now,” it implies that it would be a good or beneficial idea to start now, and that there might be negative consequences if we don’t start now.

The correct option to fill in the blank is Option C.

The sentence is in the simple past tense, which is used to talk about finished actions in the past. “He took up the letter” is a completed action, so the following action “read it aloud to his father” should also be in the simple past tense. 

Therefore, “read” is the correct choice. 

The other options “was reading”, “had read”, and “has been reading” are not in the simple past tense, so they don’t fit in this context.

The correct answer is Option D.

The completed sentence is: “When I met him he was walking down the crowded street.”

The preposition “down” is often used when referring to someone moving along a path such as a street or corridor. The other options “upon”, “into”, and “against” don’t fit as well in this context.

$$0.\overline{3}$$ can be written as $$\frac{1}{3}$$. So the possible values of x, y will be as follows.

3,1 $$\Rightarrow\ (\frac{1}{x})^{\frac{1}{y}}=\frac{1}{3}$$. Here, xy=3.

9,2 $$\Rightarrow\ (\frac{1}{x})^{\frac{1}{y}}=\left(\frac{1}{9}\right)^{\frac{1}{2}}=\frac{1}{3}$$. Here, xy=18.

27,3$$\Rightarrow\ (\frac{1}{x})^{\frac{1}{y}}=\left(\frac{1}{27}\right)^{\frac{1}{3}}=\frac{1}{3}$$. Here, xy=81.

So, option B is correct.

We can do this question by looking at the options

Clearly the 2nd option is correct as $$5^2+6^2=61$$

Hence that is the correct answer

Let's look at Option 3

$$\frac{0.011\times\ 0.011}{1.21\times\ 0.01\times\ 0.01}=\frac{11\times\ 11\times\ 100}{100\times\ 121}$$

We can clearly see that on simplification that this will give 1. Hence this is the answer

When 1 is subtracted from $$10^n$$, it always results in a series of 9s.

Let the number of 9's be n. 9(n)=4707 or n=523

Hence there are 523, 9's. Thus n=523

Now we have $$\left(\frac{1}{5}\right)^{2000}=\left(\frac{2}{10}\right)^{2000}$$

As we can see the last digit of the decimal representation will be the unit digit of 2^2000. Now the cyclicity of 2 is 4, i.e powers of 2 repeats its unit digit after every 4 units. Now divide 2000 by 4, we get remainder as 0 . So we can say that 2^2000 is equivalent to 2^4. Hence the unit digit of 2^2000 is the unit digit of 2^4. Hence the unit digit is 6

 The number of digits in $$4^{50}$$ is $$\log\ 4^{50}=50\ \log\ 4$$

or 100 log 2 = 100(0.3010)=30.10

Number of digits 30+1=31

We can simplify the LHS to $$\log\ \left(\frac{a^2}{b}\times\ \frac{b}{a^2}\right)\ =\log\ 1$$ 

Now log 1 = log(a+b) Hence a+b=1 . 

$$\frac{1}{\log_ab}\times\ \frac{1}{\log_cb}\times\ \frac{1}{\log_ac}=\frac{1}{\log_ab}\times\ \frac{\log_ca}{\log_cb}=\frac{\log_ab}{\log_ab}=1$$

Let the side of the square be a cm. Hence the area shall be $$a\ cm^2$$

Hence, the diagonal of the square shall be $$a\sqrt{\ 2}$$, and a square with this side shall have an area of $$2a\ cm^2$$

Thus, the ratio of these two areas is 1:2

For the largest possible cube (of side a) in a sphere with radius r:

Diagonal of cube = diameter of the sphere, which is $$a\sqrt{\ 3}$$= 2r, or a = $$\ \frac{\ 2r}{\sqrt{\ 3}}$$

Now, the volume of this cube is $$a^3$$, or $$\ \frac{\ 8r^3}{3\sqrt{\ 3}}\ cm^3$$

For the first case where the square (side being a cm) is inscribed in a circle, the square's diagonal is equal to the circle's diameter (2r).

Hence, 2r = a$$\sqrt{\ 2}$$, Hence a= r$$\sqrt{\ 2}$$

For the second case, where the square (side is b cm) is inscribed in the semi circle with the same radius, the radius, half of the square side, and a complete side will form a right angle triangle (from the mid point on the base of the semi circle). 

Hence, $$r^2=\ \ \frac{\ r^2}{4}\ +\ b^2$$, or b= $$\ \frac{\ 2r}{\sqrt{\ 5}}$$

Hence the area of square with side a to the area of square with side b is 5:2

Total area of the cardboard is $$20\times\ 15=300m^2$$ Area of the four squares is $$2\times\ 2\times\ 4=16\ m^2$$

Remaining area is 300-16=284 

The perimeter of the smaller ring is $$4\pi\ $$ . The perimeter of the larger ring is $$20\pi\ $$

As we can clearly see, it will take 5 rotations of smaller ring to completely cover the larger circle.

Area of the equilateral triangle park is $$16\sqrt{\ 3}=\frac{\sqrt{\ 3}}{4}a^2$$   where "a" is the length of the side of the triangle

$$a^2=64\ or\ a=8\ cm$$ Now cost of fencing triangular and square park is same, hence their perimeter will also be same. Perimeter of the square park is 24cm

Hence the length of each side of square park is 6 cm. $$\sqrt{\ 6^2+6^2}=\sqrt{\ 72}=6\sqrt{\ 2}$$

Length of each diagonal is $$6\sqrt{\ 2}cm$$

The length of glass tape required will be the sum of lengths of all the edges. Hence total length required will be  4(30+25+20)=300 cms of total tape will be required

Radius of circle at centre O = 5 m and the triangle formed is an equilateral triangle.

Let side of triangle be $$s=?$$

O is the centroid of the triangle dividing $$a:h=2:1$$

=> $$h=2.5$$ m

=> $$tan(30^\circ)=\frac{h}{\frac{s}{2}}$$

=> $$\frac{1}{\sqrt3}=\frac{5}{s}$$

=> $$s=5\sqrt3$$ m

=> Ans - (B)

Let length, breadth and height of Meeta's lunch box be 10 cm each

=> Length and Breadth of Rita's lunch box = 11 cm and height = 8 cm

Volume of a cuboid = $$lbh$$

=> Required ratio = $$\frac{11\times11\times8}{10\times10\times10}$$

= $$121:125$$

=> Ans - (D)

Number of visitors who paid for the ticket = $$\frac{90}{100}\times35000=31500$$

Let number of children be $$x$$ and number of adults = $$(31500-x)$$

According to ques,

=> $$40(31500-x)+20x=9,50,000$$

=> $$12,60,000-20x=9,50,000$$

=> $$20x=3,10,000$$

=> $$x=\frac{310000}{20}=15,500$$

=> Ans - (B)

Let radius of new sphere = $$r$$ cm

Volume of a sphere = $$\frac{4}{3}\pi r^3$$

=> $$\frac{4}{3}\pi r^3=(\frac{4}{3}\pi\times3^3)+(\frac{4}{3}\pi\times4^3)+(\frac{4}{3}\pi\times5^3)$$

=> $$r^3=27+64+125=216$$

=> $$r=\sqrt[3]{216}=6$$ cm

=> Ans - (A)

Mean of 30 observations = 150

For correcting the error, we need to subtract 135 and add 165, 

=> New average = $$\frac{(150\times30)+165-135}{30}$$

= $$\frac{150\times30+30}{30}$$

= $$150+1=151$$

=> Ans - (B)

Total students = 45, Number of boys = 30 and number of girls = 15

=> Ratio of boys : girls = 2:1

Average weight of girls is 45 kg and that of boys is 52 kg

$$\therefore$$ Average weight of class = $$\frac{52(2)+45(1)}{2+1}$$

= $$\frac{149}{3}=49.67\approx50$$ kg

=> Ans - (C)

Average of first $$n$$ even numbers = $$(n+1)$$ and average of first $$n$$ odd numbers = $$n$$

=> Average of first 10 even numbers = $$(10+1)=11$$

=> Ans - (C)

Terms : $$6, 7, x - 2, x, 17$$ and $$20$$

Since, there are 6 terms, median is the average of 3rd and 4th term

=> Median = $$\frac{x-2+x}{2}=16$$

=> $$x-1=16$$

=> $$x=17$$

=> Ans - (D)

Let the unit's digit is $$y$$ and ten's digit is $$x$$, => Number = $$10x+y$$

=> $$10x+y=7(x+y)$$

=> $$10x+y=7x+7y$$

=> $$3x=6y$$

=> $$x=2y$$ ----------------(i)

Also, $$10x+y-9=10y+x$$

=> $$9(x-y)=9$$

=> $$x-y=1$$

Substituting value from equation (i), => $$2y-y=y=1$$

=> $$x=2$$

$$\therefore$$ Original number = 21

=> Ans - (A)

Let original sum = Rs. $$6x$$

Sum invested at 3% = Rs. $$2x$$ and sum invested at 6% = Rs. $$x$$ and sum invested at 8% = Rs. $$3x$$

Simple interest = $$\frac{P\times r\times t}{100}$$

According to ques,

=> $$\frac{2x\times3\times1}{100}+\frac{x\times6\times1}{100}+\frac{3x\times8\times1}{100}=600$$

=> $$6x+6x+24x=60,000$$

=> $$x=\frac{60000}{36}=\frac{10,000}{6}$$

$$\therefore$$ Original sum = $$6\times\frac{10000}{6}=Rs.$$ $$10,000$$

=> Ans - (D)

Let principal sum = Rs. $$x$$

Rate of interest = 4% for 2 years

Compound interest = $$P[(1+\frac{r}{100})^t-1]$$

=> $$P[(1+\frac{4}{100})^2-1]=102$$

=> $$P[(\frac{26}{25})^2-1]=102$$

=> $$P(\frac{676-625}{625})=102$$

=> $$P=625\times2=Rs.$$ $$1250$$

$$\therefore$$ Simple interest = $$\frac{P\times r\times t}{100}$$

= $$\frac{1250\times4\times2}{100}=Rs.$$ $$100$$

=> Ans - (B)

Expression : $$X^{2}-Y^{2}-Z^{2}+2YZ+X+Y-Z$$

= $$x^2-(y^2+z^2-2yz)+(x+y-z)$$

= $$x^2-(y-z)^2+(x+y-z)$$

= $$[x^2-(y-z)^2]+(x+y-z)$$

Using, $$a^2-b^2=(a-b)(a+b)$$

= $$(x-y+z)(x+y-z)+(x+y-z)$$

= $$(x+y-z)(x-y+z+1)$$

=> Ans - (A)

Given : $$a + b + c = 0$$

=> $$(a+b)=-c$$

Cubing both sides, => $$(a+b)^3=(-c)^3$$

=> $$a^3+b^3+3ab(a+b)=-c^3$$

=> $$a^3+b^3+3ab(-c)=-c^3$$

=> $$a^3+b^3+c^3=3abc$$ --------------(i)

Expression : $$(a+b)^{3}+(b+c)^{3}+(c+a)^{3}$$

= $$[a^3+b^3+3ab(a+b)]+[b^3+c^3+3bc(b+c)]+[c^3+a^3+3ca(c+a)]$$

= $$[a^3+b^3+3ab(-c)]+[b^3+c^3+3bc(-a)]+[c^3+a^3+3ca(-b)]$$

= $$2(a^3+b^3+c^3)-9abc$$

Substituting value from equation (i), we get :

= $$2(3abc)-9abc=-3abc$$

$$\therefore$$ $$abc$$ is a factor of the given expression.

=> Ans - (A)

Let length and breadth of rectangle initially be 10 cm each

Area = $$A=lb=10\times10=100$$ $$cm^2$$

New length after 10% decrease = 9 cm and similarly new breadth = 11 cm

=> New area = $$A'=9\times11=99$$ $$cm^2$$

$$\therefore$$ Decrease in area = $$\frac{100-99}{100}\times100=1\%$$

=> Ans - (B)

Let son's present age = $$x$$ years and father's present age = $$y$$ years

=> $$x+y=99$$

Let $$n$$ years ago, father was same as his son's age, where $$n=y-x$$

=> $$4(x-n)=(y-n)$$

=> $$4x-4(y-x)=y-y+x$$

=> $$8x-4y=x$$

=> $$7x=4y$$

=> $$\frac{x}{y}=\frac{4}{7}$$

=> Ans - (D)

Initial selling price = Rs. $$x$$

Cost price after 15% loss = $$\frac{x}{100-15}\times100$$ --------------(i)

New selling price = Rs. $$y$$

Cost price after 15% gain = $$\frac{y}{100+15}\times100$$ -------------(ii)

Comparing equations (i) and (ii),

=> $$\frac{x}{85}=\frac{y}{115}$$

=> $$\frac{x}{y}=\frac{115}{85}=\frac{23}{17}$$

Using componendo and dividendo

=> $$\frac{y-x}{y+x}=\frac{17-23}{17+23}=\frac{6}{40}$$

=> $$\frac{y-x}{y+x}=3:20$$

=> Ans - (C)

Expression : $$\sqrt{x+\frac{x}{y}}=x\sqrt{\frac{x}{y}}$$

=> $$x+\frac{x}{y}=x^2\times\frac{x}{y}$$

=> $$1+\frac{1}{y}=\frac{x^2}{y}$$

=> $$\frac{1}{y}(x^2-1)=1$$

=> $$y=x^2-1$$

=> Ans - (B)

A number when divided by 195 leaves a remainder 47

Let the number be $$N=195q+47$$

Now, if N is divided by 15, the remainder is = $$(195q+47)\%15$$

Since, 195 is completely divided by 15, thus remainder depends on 47, => $$47=3\times15+2$$

=> Remainder = 2

=> Ans - (C)

Given = a : b = 3 : 4; b : c = 4 : 7

=> $$a:b:c=3:4:7$$

Let $$a=3,b=4,c=7$$

$$\therefore$$ $$\frac{a+b+c}{c}$$

= $$\frac{3+4+7}{7}=\frac{14}{7}=2$$

=> Ans - (B)

The speeds of the two trains in m/s would be $$80\times\ \frac{5}{18}=22.22$$ m/s and $$55\times\ \frac{5}{18}=15.277$$ m/s
Giving their relative speed to be 37.5 m/s

The total distance both trains essentially have to cover would be the distance between them + length of train 1 + length of train 2
Distance to be travelled = 90+120+90 = 300m

The time taken would then be $$\frac{300}{37.5}=8$$ second

Therefore, Option C is the correct answer. 

Average speed is the harmonic mean of both speeds = $$2\div(\frac{1}{60}+\frac{1}{40})$$

= $$2\div(\frac{2+3}{120})$$

= $$2\times\frac{120}{5}=48$$ km/hr

=> Ans - (B)

Let total work to be done = 96 units

Thus, 12 men complete 12 units of work each day, thus 1 man's efficiency = 1 unit/day

Work done in first 3 days = 36 units

Now, remaining work, i.e. 60 units must be completed in 4 days

=> Number of men required = $$\frac{60}{4}=15$$ 

Thus, 3 more men are required.

=> Ans - (A)

Let total work = 18 units

Let B's efficiency = $$x$$ units/day and A's efficiency = $$2x$$ units/day

According to ques, working together, they finish work in = $$(x+2x)\times18=18$$

=> $$3x=1$$

=> $$x=\frac{1}{3}$$

$$\therefore$$ Time taken by A alone to finish the work = $$\frac{18}{\frac{1}{3}}=54$$ days

=> Ans - (D)

Two pipes A and B can fill a tank in 24 hours and 30 hours respectively.

Time taken by both pipes together = $$1\div(\frac{1}{24}+\frac{1}{30})$$

= $$1\div(\frac{5+4}{120})$$

= $$\frac{120}{9}=\frac{40}{3}$$ hours

=> Ans - (B)

Let quantity of bucket = $$9$$ units

Here, 4 units is filled in 1 minute

=> Remaining, 5 units will be filled in = $$\frac{5}{4}$$ min

=> Ans - (C)

The statement talks about the poor yield of cotton even after the introduction of a new variety of seeds. 

We shall try negating the assumption and see if it invalidates the main statement as well for it to be a valid conclusion.

1. Had the yield not been expected to improve after the introduction of a new variety of seeds, the main statement would not be mentioned the same and seeds wouldn't have been introduced in the first place. Hence, a valid assumption.

2. Had the yield been adequate before the new seeds, they would not have been introduced in the first place. Hence, an invalid assumption. 

The statement talks about the changed financial priorities of the institute and not having provisions for recruiting additional faculty.

We shall try negating the assumption and see if it also invalidates the main statement, for it to be a valid conclusion.

1. If the appointment would not require funds, the same should not have been removed from the list of budgetary provisions. Hence, a valid assumption.

2. The statement clearly mentions about changed financial priorities of the institute, hence it is clear that there are other important areas to focus than faculty recruitment at the current point. Hence, a valid assumption. 

The statement talks about the urgent need to repair the office building along with painting.

We shall try negating the assumption and see if it also invalidates the main statement for it to be a valid conclusion.

1. The main statement does not mention the connection between the efficiency of the employees and the condition of the building. Hence, negating the contention of improved efficiency will not have any effect on the main premise. This makes it an invalid assumption. 

2. The repairing will definitely require funds, but the same is not an assumption for the main statement, as it merely talks about the need to repair. Hence, an invalid assumption.

The statement talks about the lost opportunity of carrying out reforms for the election system when most of the recommendations by the Goswami committee were rejected due to partisan reasons. 

We shall try negating the assumption and see if it also invalidates the main statement, for it to be a valid conclusion.

1. Had the committee not laid down good recommendations, there wouldn't be an instance of loss of opportunity in carrying reforms. Hence, it is a valid assumption.

2. The committee's recommendations were rejected for partisan reasons. However, there is no sufficient evidence to claim that most of the decisions are guided by partisan reasons. Hence, an invalid assumption. 

The statement talks about Shri Roy taking over as the new director and the hope of seeing improvements in the administration. 

We shall try negating the assumption and see if it also invalidates the main statement, for it to be a valid conclusion.

1. The statement clearly mentions 'new director', which makes this an invalid assumption. 

2. Had the director not been supposed to look after the administration, there should not be any expectation to see improvements in the same. Hence, it is a valid assumption.

Following are the conditions: 

1. The following can be the possibilities with respect to P and V: P/V/None

2. The following can be the possibilities with respect to T and Q: Q...T

3. The following can be the possibilities with respect to R and V: R...V

4. The last has to be S or U. 

Now, we shall test each of the options.

Option 1: If we can find a combination with P at the third place, this option will be incorrect. A possible combination can be: QTPW(S/U). Since all conditions are met in this combination, we know this option is incorrect. 

Option 2: If we can find a combination with Q at the third place, this option will be incorrect. A possible combination can be: PWQT(S/U). Since all conditions are met in this combination, we know this option is incorrect.

Option 3: If we can find a combination with R at the fourth place, this option will be incorrect. There cannot be any valid combination since V has to come after R, but the last element shall be S/U. Hence, this is a correct option. 

Option 4: If we can find a combination with U at the fourth place, this option will be incorrect. A possible combination can be: PQTUS. Since all conditions are met in this combination, we know this option is incorrect.

Following are the conditions:

1. The following can be the possibilities with respect to P and V: P/V/None

2. The following can be the possibilities with respect to T and Q: Q...T

3. The following can be the possibilities with respect to R and V: R...V

4. The last has to be S or U.

If R and W are mandatorily in the list, we need to have V as well (condition with R). 

Now, RWV are in the list. For the other two: We need to have at least one of S/U for the end. Both of them will also be fine. 

Hence, one set can be R,W,V,S,U.

We can also have T instead of one of S/U, as we cannot have P (since it cannot come with V). This makes another possible set as: R,W,V,T, S/U. Hence, Option B is correct. 

The current list is : P, Q, W, T, U

Now, we shall have three elements from this list and two from the remaining ones: R,S,V.

We shall test each of the options: 

1. QRVTU: This is a valid combination as it satisfies all the conditions.

2. QTVWS: This is a valid combination as it satisfies all the conditions.

3. WRVTU: This is a valid combination as it satisfies all the conditions.

4. WTSPU: We can only take three elements out of  P, Q, W, T, U. However, this option takes four, hence an invalid option.

We shall test each of the options:

1. PRVSU: We cannot have P and V together, hence an invalid choice. 

2. QSRVU: If Q is selected, T must be operated sometime after Q. This condition is violated in the given case, hence an invalid option. 

3. TURVS: This case satisfies all the given conditions.

4. UQSTW: The last element has to be one from S or U, which is not there in the given case. Hence, an invalid option. 

We shall test each of the options with R in the third place. 

1. _ Q R_ _: In this case, we know that T has to come after Q, and V after R. However, this will violate the rule of having one of S/U at the end. Hence, an invalid combination and the correct choice for the question. 

2. _ S R _ _: With this, we can have TSRVU as one of the valid sequences. 

3. _ T R _ _: With this, we can have QTRVU as one of the valid sequences.

4. _ U R _ _: With this, we can have TURVS as one of the valid sequences.

Statement: Some apples are watermelons. All watermelons are fresh. Some potatoes are fresh.

Now, let us try to negate each option with a possible scenario, and if we find an option that cannot be negated, that shall be the correct answer. 

1. Some apples are fresh: We know that every watermelon is fresh. We also know that some apples are watermelons (which are fresh). Hence, those apples that are watermelons must also be fresh in every case. This is a valid conclusion. 

2. Some potatoes are apples: We know that some potatoes are fresh, while all watermelons are fresh. It is also given that some apples are watermelons. We can form a possible scenario where no potatoes are watermelons (fresh encompassing both of them as two separate subsets), and then some apples being watermelons. From this, we can negate the case of some potatoes being apples. 

3. Some watermelons are potatoes: e know that some potatoes are fresh, while all watermelons are fresh. We can form a possible scenario where no potatoes are watermelons (fresh encompassing both of them as two separate subsets). From this, we can negate the case of some watermelons being potatoes. 

4. Some watermelons are apples: It is clearly given that some apples are watermelons. Hence, we are sure that some watermelons will always be apples, if not all. This is a valid conclusion. 

We know: All pens are pencils. Some pens are erasers. Some erasers are clips.

We shall now test each of the conclusions and try negating them. The ones that will be necessarily true in every case shall be valid in nature. 

1 and 2. Some clips are pens, and no clip is a pen: We know that some pens are erasers and some erasers are in-turn clips. Hence, clips and pens can overlap, or they can be disjointed sets. There is no other possibility. Hence, either of 1 or 2 shall be true. 

3.  Some erasers are pencils: We know that all pens are pencils, and some pens are erasers. Hence, there are definitely some pens that are both erasers and pencils, making at least a small part of erasers overlap with pencils. This makes 3 a valid conclusion.

4. No eraser is a pencil: This is an invalid conclusion as there are definitely some pens that are both erasers and pencils, making at least a small part of erasers overlap with pencils. 

We know: Some books are papers. Some papers are plastic. No plastic is black.

We shall now test each of the conclusions by negating them, and the ones which shall hold true in every case are valid in nature. 

1. Some papers are not black: This is a true statement since some papers are plastic, and no plastic can be black. Hence, The papers which are plastic are definitely not black. 

2. All papers are not black: We cannot be sure about this conclusion, as we merely know that papers that are plastic are definitely not black. However, we don't have any information about the papers which are not plastic, they may or may not be black. 

3. Some papers are black: Again, we cannot be sure about this conclusion because there can be a case when papers and black are totally disjointed sets. 

4. Some books are black: Invalid conclusion by the same logic as mentioned in 3. 

We know: Some doors are windows. All windows are black. Some black are brown.

We shall now test each option by negating them with a possible scenario, and the one that holds true for every scenario shall be a valid conclusion.

1 and 4. Some windows are brown, and no windows are brown. It is clear from the given information that there can be a possibility of windows overlapping with brown as all windows are black and some black are brown. However, we cannot be sure that some windows will fall under brown. Hence, one of the two conclusions shall definitely be true.

2. All doors are black: We only know that some doors are windows, that in turn, are black. However, we cannot say for sure that all doors can be classified as windows for them to be black. Hence, an invalid conclusion.

3. Some doors are black: It is known that some doors are windows, and all windows are black. Hence, the doors that are windows shall also be black. This is a valid conclusion. 

We know: All teachers are doctors. All doctors are engineers. All engineers are typists.

Now, we shall test each option by finding a scenario where the conclusion would not hold true. One which shall hold true in all the cases shall be valid in nature. 

1. It is clear that all teachers are typists, because of the given data. Hence, we can conclude that some typists must be teachers. 

2. This is a valid conclusion by the same logic as Option 1.

3. Since all doctors are engineers, some engineers shall definitely be doctors. This is a valid conclusion.

4. We only know that all teachers are doctors, but we cannot say vice versa. It might be possible that there are doctors that cannot be classified as teachers. Hence, an invalid conclusion. 

The statement talks about an increase in air export volumes that is causing problems for air cargo argents. 

The first course of action talks about airlines and air cargo working together for a solution. However, the statement mentions nothing about the airlines, and hence, we cannot say whether the problem even concerns the airlines. Hence, it is an invalid course of action.

The second course of action talks about finding the reason for the increased volume, that has eventually caused problems for air cargo. This is a valid course of action, since it will help in coming up with potential solutions.

The statement talks about a world conference that laid down some framework with respect to meeting the learning needs of children. 

The first course of action states that India shall implement the framework, which is a valid statement considering the utility of the said framework. Hence, a valid course of action. 

The second course of action states that India shall conduct a similar conference immediately, which seems to be serving no purpose. This is because the framework has already been laid down and widely discussed, thereby making another conference a not-so-urgent event. Hence, an invalid course of action.

The statement talks about many students being absent from the school.

The first course of action talks about opening new schools, which seems to be irrelevant considering the issue of absenteeism even in the current school.

The second course of action talks about finding the reason for absenteeism, which is definitely a good idea to come up with potential solutions in for combating the issue. 

The statement talks about India's share in global agricultural trade being less than the share of agricultural exports to total exports.

Both courses of action seem to be invalid in this case. This is because we neither know whether the issue is due to the lower agricultural production nor if the reduction of export of non-agricultural commodities is a potential solution.

The statement talks about the requirement of natural resources for developing India's tourist spots, as well as the vast number of potential tourist attractions that are present. 

The first course of action makes sense since India has a vast coastal line, and it can be turned into a tourist attraction. 

The second course of action also makes sense since there are various potential tourist attractions in India. 

Let us test each statement and see if we can arrive at the number of daughters L has.

1 talks about the number of daughters that R's father has. However, to answer the question, we need additional information about the relation between R and L. This is given by 2, that ‘T’ is R’s sister and daughter of L. Using this, we know L is a parent of R. Hence, L has three daughters, which we get by combining both 1 and 2. 

If we combine both P and Q, we get to know that M is the sister of C. However, we cannot answer the question pertaining to C's brother. Hence, the data together is insufficient. 

Let us test each statement and see whether we can get the number of Telugu novels.

1. There are only three types of novels, and of the one thousand novels is the library, fifty percent novels are in English and Hindi. This means that the remaining 500 books are Telugu novels. 

2. Even after knowing that Hindi novels are double in number than English novels, we have no clue about the exact number of any of these categories. Hence, we can't find the number of Telugu novels from this data.

Even when we know the date on which the statement was made and the fact that it is a leap year, we still don't know about the date of expiry of the driving license. Hence, we can't give the exact date before which the license shall be renewed. 

Since the area is 484 sq. cm:

P. If it costs Rs. 912 to fence the playground, we need to get the cost of fencing per cm to arrive at the perimeter of the playground. However, the same is not mentioned, and hence, we cannot answer the question using this data. 

Q. If the playground is a perfect square, we can use the given area to find the value of each of the sides. The sides, thus, are of 22 cm. From this, we can find the perimeter, which is four times the side, that becomes 88 cm. 

Out of Ear, Lungs, Heart, and Kidney: Ear is a body part, while others are functioning organs. 

The path can be traced like:
After moving to 10 m to west, he moves 20 m north, and then again 10 m east. The movement in west and then east will cancel each other, further making the movement to north the only effective one. Hence, he is 20 m north from the initial starting point.

The statement talks about a connection between ulcers and anxiety. However, it also states that some happy-go-lucky people also suffer from ulcers. Now, we need to have a strong set of data to strengthen the connection between ulcers and anxiety. 

1. This option talks about peptic ulcer, which is a specific case of ulcers. Further, this is a mere statement and hence doesn't add value to the original information. Hence, a weak option.

2. Even if anxiety is more harmful than ulcers, we cannot use this to strengthen the association between anxiety and ulcers. 

3. Even if about 90% of women suffer from ulcers, we don't get any input to support the association of ulcers and anxiety. 

4. If more than 65% of the ulcer patients were found to be high on anxiety, we can strongly claim the association of anxiety and ulcers. Hence, a strong statement to substantiate the premise. 

It is best to eliminate each option in this question. 

1. This can be a valid conclusion owing to the line Research in this area is extremely homogeneous, as anywhere from 50% to 85% of this literature employs scales developed by APA.

2. The statement mentions that 'employs scales developed by APA'. The word 'scales' shows that there are more than one scale developed by APA. 

3. It is mentioned that role conflict and ambiguity are the 'most widely' examined source, which shows that there might be other sources as well. 

4. There is nothing to conclude that the area has a dearth of literature. 

Hence, the first option is correct. 

We know that: A>B, C>D, and D>E. 

To know who is taller, we need a link connecting A>B to the other two conditions. 

1. Even if A is taller than E and D, we don't know about its relation with C. Hence, we cannot find the tallest person. 

2. Even if C is taller than B, we cannot deduce the taller person among A and C. Hence, this is an incorrect choice. 

3. Even if A is taller than D, we cannot deduce the taller person among A and C. Hence, this is an incorrect choice.

4. If E is taller than A, we know that C will be the tallest. Hence, this is the correct choice.

If it is known that the militants were hiding in area X and cannot be traced after the search, it is clear that they either kept hiding with the support of locals or ran away before the search. There cannot be any other possibility. Hence, either of the statements is correct. 

It is given that a lot of officers were transferred by the Chief Secretary, except for those who kept him in good humor. 

R1: The main statement mentions about 'good humor', which is insufficient to say that the Chief Secretary is a jolly person. 

R2: Since the only officers who were not transferred are the ones who kept the Chief Secretary in good humour, it is clear that the transfers were made on the personal feelings of the Chief Secretary. Hence, a valid statement. 

The two statements focus on the party losing in the election and the noticeable lack of enthusiasm among the workers. However, there is no direct correlation between the two statements as expressed in the question. 

Hence, we cannot state whether the party workers play an important role, because no such correlation has been expressed between losing the elections and lack of enthusiasm. These two might be two stand-alone statements. 

From the same logic, we cannot say that had the workers been dedicated enough, the win was a sure shot thing. 

We shall mainly focus on the line which had faulty designs or inferior material.

Hence, it is clear that either the reason is faulty design or interior material. 

This means either R1 or R2 is true.

As per the statements, if a person dies in police custody, the police official is summoned. Further, if the atrocities are proved, they are punishable under law. 

Hence, it is clear that the law is considerate for criminals, providing a safeguard to them by preventing them from atrocities. 

However, we cannot state that a person cannot die a natural death in the custody. 

In this, we shall test each option to arrive at the correct pair.

1. No wealthy persons are vagrants, All lawyers are wealthy persons, Some lawyers are vagrants: This is logically inconsistent, because it can be clearly seen that wealthy people can't be vagrants, and all lawyers are wealthy people. Hence, they cannot be vagrants.

2. All lawyers are wealthy persons, No lawyers are vagrants, All lawyers are vagrants: The second and third statements are contradictory in nature, hence logically inconsistent. 

3. No wealthy persons are vagrants, All lawyers are wealthy persons, All lawyers are vagrants: This is logically inconsistent by the same logic as Option 1. 

4. No wealthy persons are vagrants, All lawyers are wealthy persons, No lawyers are vagrant: This is logically consistent because it can be clearly seen that wealthy people can't be vagrants, and all lawyers are wealthy people. Hence, they cannot be vagrants. 

Option A. C and E statements directly imply A statement.
Option B. Both voters and citizens are inside the "residents" circle, but they might not touch each other at all. You can't prove they overlap.
Option C. Existential Fallacy: While "All voters are residents" is a valid deduction, "Some residents are voters" assumes that at least one voter actually exists. In formal logic, "All" does not automatically imply "Some."
Option D. Direct Contradiction: Premise (A) says voters are residents, and Premise (E) says those same voters are citizens. Therefore, some citizens must be residents, making "No citizen is a resident" impossible.

That's why the correct option is A.

We shall test each option to find whether they are logically consistent or not: 

1. CBA: It is clearly given that no preacher is an intellectual, while some intellectuals are persons of unfailing vigour. From this, we cannot conclude that some preachers are persons of unfailing vigour because there might be a case where preachers and persons with unfailing vigour are disjointed sets. 

2. CBD: It is clearly given that no preacher is an intellectual, while some intellectuals are persons of unfailing vigour. From this, we can definitely conclude that some persons with unfailing vigour are not preachers, exactly those who are intellectuals. 

3. ABD: We cannot conclude that some persons of unfailing vigour are not preachers, because there might be a case where both of them are overlapping sets with the same elements in total.

4. CBE: In this, we don't have any relationship given about persons with unfailing vigour and preachers. Hence, an invalid connection. 

BDC (Correct): If all game-seers were at the dance (B) and some game-seers are students (D), then those specific students must have been at the dance (C).

ABC (Incorrect): This set is redundant; if all students saw the game (A) and all game-seers were at the dance (B), the conclusion should be "All students were at the dance," not just "Some" (C).

ACF (Incorrect): Statement (F) directly contradicts the combination of (A) and (C) by claiming no one at the dance saw the game.

CDA (Incorrect): Knowing some students were at the dance (C) and some game-seers are students (D) provides no logical basis to conclude that all students saw the game (A).
Thus, the correct answer is Option A.

The logical consistency of the combination CDF is derived from a standard syllogistic structure where the first two statements act as premises that necessarily lead to the third statement as a conclusion. Statement (D) establishes a universal relationship by asserting that "All shy and retiring people are intellectuals," which places the entire group of shy and retiring people within the larger category of intellectuals. Statement (C) provides a negative universal constraint, stating that "No intellectuals are successful politicians," effectively creating a barrier between the intellectual category and the group of successful politicians. Since all shy and retiring people are contained within the intellectual group, and no intellectuals can be successful politicians, it logically follows that no member of the shy and retiring group can be a successful politician either. This direct deduction perfectly matches statement (F), "No shy and retiring people are successful politicians," making the set a valid logical argument.