[Download PDF] SBI Associate 2011 PO Paper with Solutions

Instructions

What will come in place of question mark (?) in the following questions:

Question 101

$$32\cdot05$$% of 259.99=?

Video Solution

Solution

The problem can be solved quickly by rounding off,

32.05% ~32 and 259.99~ 260

Now, 32% of 260 = 83.2

Question 102

$$\frac{1}{8} of \frac{2}{3} of \frac{3}{5}$$ of 1715=?

Video Solution

Solution

Now, $$\frac{1}{8} of \frac{2}{3} $$= (1/8)*(2/3)=1/12

Also, ( $$\frac{1}{8} of \frac{2}{3}$$ ) of $$\frac{3}{5}$$ = (1/12) * (3/5) = 1/20
Now, (1/20) 0f 1715= (1/20)*1715 = 85

Question 103

$$25\cdot05\times123\cdot95+388\cdot999\times15\cdot001=?$$

Video Solution

Solution

Here we are approximating 25.05~25, 123.95~124, 388.99~389, 15.001~15.

The question can be rewritten as,

25*123+388*15=8935
Hence the correct option is 8935.

Question 104

$$561\div35\cdot05\times19\cdot99$$=?

Video Solution

Solution

By approximating 561~560, 19.99~20 and 35.05~ 35 for easier calculation,

the question can be written as,

560*(20/35)=320

Question 105

$$(15\cdot01)^{2}\times\sqrt{730}=?$$

Video Solution

Solution

The question can be reframed as,

$$15^{2}$$*$$\sqrt(729)$$=$$225\times27$$=607

Instructions

In each of these question a number series is given.In each series only one number is wrong.Find out the wrong numbers

Question 106

3601, 3602, 1803, 604, 154, 36, 12

Video Solution

Solution

In the given series, nth term is obtained by - (Previous term/(n-1) ) +(n-1).

Hence the 5th term should be (604/4)+4 = 155.

However 5th term is given as 154.
Hence, 154 is wrong term in the given series.

Question 107

4, 12, 42, 196, 1005, 6066, 42511

Video Solution

Solution

In this question, the nth term is obtained by (previous term*n + n^2).

Hence, after 12, the number would be (12*3+9)= 45

Therefore, the correct option is 45.

Question 108

2, 8, 12, 20, 30, 42, 56

Video Solution

Solution

Here the consecutive difference between the terms is incremented by 2 for the series.

Hence, after 2, the number should be 6.

Question 109

32, 16, 24, 65, 210, 945, 5197.5

Video Solution

Solution

Here the sucessive numbers are multiplied by .5,1.5.2.5....

Hence, in place of 65 the number should be 24*2.5=60.

Therefore, the incorrect number for series is 65.

Question 110

7, 13, 25, 49, 97, 194, 385

Video Solution

Solution

Here, in this series, the nth term is (previous term + 6*2n-2 )

Hence, in place of 194 the term should be (97+6*24) = 193

CAT Content

SBI Associate 2011 PO

$$32\cdot05$$% of 259.99=?

$$\frac{1}{8} of \frac{2}{3} of \frac{3}{5}$$ of 1715=?

$$25\cdot05\times123\cdot95+388\cdot999\times15\cdot001=?$$

$$561\div35\cdot05\times19\cdot99$$=?

$$(15\cdot01)^{2}\times\sqrt{730}=?$$

3601, 3602, 1803, 604, 154, 36, 12

4, 12, 42, 196, 1005, 6066, 42511

2, 8, 12, 20, 30, 42, 56

32, 16, 24, 65, 210, 945, 5197.5

7, 13, 25, 49, 97, 194, 385

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