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NTA JEE Main 25th April 2013 Online - Mathematics

For the following questions answer them individually

If $$p$$ and $$q$$ are non-zero real numbers and $$\alpha^3 + \beta^3 = -p$$, $$\alpha\beta = q$$, then a quadratic equation whose roots are $$\frac{\alpha^2}{\beta}$$, $$\frac{\beta^2}{\alpha}$$ is :

Let z satisfy $$|z| = 1$$ and $$z = 1 - \bar{z}$$.
Statement 1 : z is a real number.
Statement 2 : Principal argument of z is $$\frac{\pi}{3}$$.

5-digit numbers are to be formed using 2, 3, 5, 7, 9 without repeating the digits. If $$p$$ be the number of such numbers that exceed 20000 and $$q$$ be the number of those that lie between 30000 and 90000, then $$p : q$$ is:

If for positive integers $$r > 1$$, $$n > 2$$, the coefficients of the $$(3r)^{th}$$ and $$(r+2)^{th}$$ powers of $$x$$ in the expansion of $$(1 + x)^{2n}$$ are equal, then $$n$$ is equal to:

Let $$x \in (0, 1)$$. The set of all $$x$$ such that $$\sin^{-1}x > \cos^{-1}x$$, is the interval:

Statement 1: The only circle having radius $$\sqrt{10}$$ and a diameter along line $$2x + y = 5$$ is $$x^2 + y^2 - 6x + 2y = 0$$.
Statement 2: $$2x + y = 5$$ is a normal to the circle $$x^2 + y^2 - 6x + 2y = 0$$.

A point on the ellipse, $$4x^2 + 9y^2 = 36$$, where the normal is parallel to the line, $$4x - 2y - 5 = 0$$, is :

Consider the function : $$f(x) = [x] + |1 - x|$$, $$-1 \leq x \leq 3$$ where [x] is the greatest integer function.
Statement 1: $$f$$ is not continuous at $$x = 0, 1, 2$$ and 3.
Statement 2: f(x) =$$\begin{cases}-x, & -1 \le x < 0 \\1 - x, & 0 \le x < 1 \\1 + x, & 1 \le x < 2 \\2 + x, & 2 \le x \le 3\end{cases}$$

Let $$f : [-2, 3] \rightarrow [0, \infty)$$ be a continuous function such that $$f(1-x) = f(x)$$ for all $$x \in [-2, 3]$$. If $$R_1$$ is the numerical value of the area of the region bounded by $$y = f(x)$$, $$x = -2$$, $$x = 3$$ and the axis of x and $$R_2 = \int_{-2}^{3} xf(x)dx$$, then :

Let $$\vec{a} = 2\hat{i} + \hat{j} - 2\hat{k}$$, $$\vec{b} = \hat{i} + \hat{j}$$. If $$\vec{c}$$ is a vector such that $$\vec{a} \cdot \vec{c} = |\vec{c}|$$, $$|\vec{c} - \vec{a}| = 2\sqrt{2}$$ and the angle between $$\vec{a} \times \vec{b}$$ and $$\vec{c}$$ is 30°, then $$|(\vec{a} \times \vec{b}) \times \vec{c}|$$ equals:

Let A(-3, 2) and B(-2, 1) be the vertices of a triangle ABC. If the centroid of this triangle lies on the line $$3x + 4y + 2 = 0$$, then the vertex C lies on the line :

Let ABC be a triangle with vertices at points A(2, 3, 5), B(-1, 3, 2) and C($$\lambda$$, 5, $$\mu$$) in three dimensional space. If the median through A is equally inclined with the axes, then $$(\lambda, \mu)$$ is equal to:

The equation of a plane through the line of intersection of the planes $$x + 2y = 3$$, $$y - 2z + 1 = 0$$, and perpendicular to the first plane is :

If the events A and B are mutually exclusive events such that $$P(A) = \frac{3x+1}{3}$$ and $$P(B) = \frac{1-x}{4}$$, then the set of possible values of x lies in the interval :