$$ABCD$$ is a parallelogram. The measure of $$\angle ABC = 60^\circ$$. The bisector of $$\angle BAD$$ (dividing $$\angle BAD$$ in two equal halves) meets the side $$DC$$ in point $$E$$ such that $$E$$ is the midpoint of side $$DC$$. If the length of segment $$AE = 6\text{ cm}$$, then find Perimeter of $$\triangle ADE$$ + perimeter of $$\square ABCE$$.

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