MAT 2009 Question Paper

Number of inputs at B = $$1200$$

Number of outputs from B = $$550+250=800$$

Now, input - output = demand

=> Number of units demanded in B = $$1200-800=400$$

=> Ans - (A)

Number of inputs at C = $$M+250$$

Total supply from C (outputs) = $$800+300=1100$$

Number of units demanded at C = $$225$$ units

Now, input - output = demand

=> $$M+250-1100=225$$

=> $$M=1075$$

=> Ans - (B)

Total demand in E = Total input in E = $$550+800+650=2000$$

Now, E's demand is 80% of A,

=> Total demand in A = $$2000\times\frac{100}{80}=2500$$

=> Ans - (B)

Exports of petroleum and crude in 1998-99 = 2.3%

Exports of petroleum and crude in 2002-03 = 4.5%

=> Percentage increase = $$\frac{(4.5-2.3)}{2.3}\times100\approx95.65\%$$

=> Ans - (A)

Exports of leather products in 2000-2001 = 224.10 million

=> India's exports in 2000-2001 = $$224.10\times\frac{100}{5}\times\frac{100}{74.7}$$

= $$3\times20\times100=6000$$ million dollars

=> Ans - (B)

Exports of gems and jewellery in 1999-2000 = 300 million

=> India's exports in 1999-2000 = $$300\times\frac{100}{16.6}\times\frac{100}{77.6}\approx2330$$ million

After 150% increase, India's exports in 2002-03 = $$2.5\times2330=5825$$ million

$$\therefore$$ Value (in millions) of the exports of ores and minerals in 2002-2003 = $$\frac{3.6}{100}\times5825\approx209.7$$ million

=> Ans - (D)

Let India's exports in 1998-99 be Rs. 100 and thus in 2002-03 = Rs. 120

Thus, Engineering goods in 1998-99 = $$\frac{12.5}{100}\times\frac{73.6}{100}\times100=\frac{73.6}{8}=9.2$$

Engineering goods in 2002-03 = $$\frac{16.6}{100}\times\frac{77.4}{100}\times120=\frac{73.6}{8}=15.4$$

$$\therefore$$ Percentage increase = $$\frac{(15.4-9.2)}{9.2}\times100\approx68\%$$

=> Ans - (A)

Difference between the maximum and the minimum production of polyethylene in 2003-04 = $$108-20=88$$

Difference between the maximum and the minimum production of polypropylene in 2003-04 = $$21-15.4=5.6$$

=> Required ratio = $$\frac{88}{5.6}\approx16$$

=> Ans - (C)

Maximum production of polyethylene in 2004-05 = 100 (January)

Minimum production of polyethylene in 2003-04 = 20 (February)

=> Required ratio = $$\frac{100}{20}=5$$

=> Ans - (A)

Production of Polyethylene and Nylon has never been equal in 2003-04 and 2004-05, but Polypropylene's production was equal once in 2003-04 and 2004-05 (in January).

=> Ans - (B)