IIFT 2021 Slot 1 Question Paper (23rd Dec)

From Statement 2, it can be said that R is the only male candidate from MBBS and Q is a selected female engineering student.

From Statement 4, T is in Fashion Technology, and P is an engineer. V is unselected male.

U is from economics and was selected with a score of 65.

From Statement 5, W is a CA, and Y and S scored 80 and 65, respectively.

Thus, 2 students are from Engineering, CA, and Economics, while the Fashion and MBBS have only 1 student. Thus, 2 students are law graduates.

Also, since U and S scored a score of 65 and U is from economics, S will also be from economics.

Since 1 student each from law and CA are left, X and Y are from Law and CA.

Since W scored 70 and Y scored 80, X is a CA graduate, and Y is from the law.

Also, since MBBS does not have the lowest Silo, thus, engineering will have the lowest Silo.

The Silo of MBBS will be 75, and that of the engineer will be 60.

From statement 3, since W is selected, X will not be selected.

Now since 2 law students and 1 CA is not selected, all the other candidates will be selected(since only 3 people were rejected).

Since both the candidates from Engineering and Economics were selected, the correct answer will be 2.

Thus, B is the correct option.

From Statement 2, it can be said that R is the only male candidate from MBBS and Q is a selected female engineering student.

From Statement 4, T is in Fashion Technology, and P is an engineer. V is unselected male.

U is from economics and was selected with a score of 65.

From Statement 5, W is a CA, and Y and S scored 80 and 65, respectively.

Thus, 2 students are from Engineering, CA, and Economics, while the Fashion and MBBS have only 1 student. Thus, 2 students are law graduates.

Also, since U and S scored a score of 65 and U is from economics, S will also be from economics.

Since 1 student each from law and CA are left, X and Y are from Law and CA.

Since W scored 70 and Y scored 80, X is a CA graduate, and Y is from the law.

Also, since MBBS does not have the lowest Silo, thus, engineering will have the lowest Silo.

The Silo of MBBS will be 75, and that of the engineer will be 60.

From statement 3, since W is selected, X will not be selected.

Now since 2 law students and 1 CA is not selected, all the other candidates will be selected(since only 3 people were rejected).

Since 3 out of 4 males are getting selected and V is already rejected, all the other rejected candidates are female.

Thus, X is a female rejected candidate from CA.

The correct option is C.

From Statement 2, it can be said that R is the only male candidate from MBBS and Q is a selected female engineering student.

From Statement 4, T is in Fashion Technology, and P is an engineer. V is unselected male.

U is from economics and was selected with a score of 65.

From Statement 5, W is a CA, and Y and S scored 80 and 65, respectively.

Thus, 2 students are from Engineering, CA, and Economics, while the Fashion and MBBS have only 1 student. Thus, 2 students are law graduates.

Also, since U and S scored a score of 65 and U is from economics, S will also be from economics.

Since 1 student each from law and CA are left, X and Y are from Law and CA.

Since W scored 70 and Y scored 80, X is a CA graduate, and Y is from the law.

Also, since MBBS does not have the lowest Silo, thus, engineering will have the lowest Silo.

The Silo of MBBS will be 75, and that of the engineer will be 60.

From statement 3, since W is selected, X will not be selected.

Now since 2 law students and 1 CA is not selected, all the other candidates will be selected(since only 3 people were rejected).

The maximum possible difference will be when T is female and U/S is male.

The difference in silos = $$85-60=25$$.

Thus, the correct option is C.

From Statement 2, it can be said that R is the only male candidate from MBBS and Q is a selected female engineering student.

From Statement 4, T is in Fashion Technology, and P is an engineer. V is unselected male.

U is from economics and was selected with a score of 65.

From Statement 5, W is a CA, and Y and S scored 80 and 65, respectively.

Thus, 2 students are from Engineering, CA, and Economics, while the Fashion and MBBS have only 1 student. Thus, 2 students are law graduates.

Also, since U and S scored a score of 65 and U is from economics, S will also be from economics.

Since 1 student each from law and CA are left, X and Y are from Law and CA.

Since W scored 70 and Y scored 80, X is a CA graduate, and Y is from the law.

Also, since MBBS does not have the lowest Silo, thus, engineering will have the lowest Silo.

The Silo of MBBS will be 75, and that of the engineer will be 60.

From statement 3, since W is selected, X will not be selected.

Now since 2 law students and 1 CA is not selected, all the other candidates will be selected(since only 3 people were rejected).

Since only male V is not selected, he will move up the waiting list.

Thus, the correct option is A.

Since A is moving from Gate 1 to Gate 2 and then coming back to Gate 1, the total time for completion of one round will be 5 minutes.

After completion of 2 rounds, i.e., after 10 minutes, A will leave for the third round.

Thus, the correct answer is B.

It is given that D left at 1:15. Since, B, A, C, D left at a gap of 2 mins. So, the time at which they left the office will be as follows.

The path taken by A,B takes 4 mins to get them to the opposite gate. And that of C, D takes 6 mins. The time when they reached the other gate is as follows. 

The time taken to reach the gate where each started is as follow.

So, C and B meet at gate 2 at 1:13. Also, D and A meet at gate 2 at 1:15.
But these two are not in the options. So, let's check the next cycle.

They start the next cycle immediately after this cycle.

The time they again reach the opposite cycle is as follows.

So, A and C meet at gate 2 at 1:20. So, Option B is correct.

Now it is given that the total employees are 90, where $$Y+3\le7\ $$ or $$Y\le4$$

So, $$39+3X+2Y\ =\ 90$$

$$3X+2Y\ =\ 51$$

$$X=\ \frac{\left(51-2Y\right)}{3}$$

Now, since $$Y\le4$$, Y can only be 3.

Thus, X will be 15.

Now, total employees in Hilton = $$2X+2Y+9=36+9=45$$

Thus, the correct option is C.

Now it is given that the total employees are 90, where $$Y+3\le7\ $$ or $$Y\le4$$

So, $$39+3X+2Y\ =\ 90$$

$$3X+2Y\ =\ 51$$

$$X=\ \frac{\left(51-2Y\right)}{3}$$

Now, since $$Y\le4$$, Y can only be 3.

Thus, X will be 15.

The number of employees in Trident and Hilton will be Y + 3 = 6.

Thus, the correct answer will be B.

The series is in the form of $$2na_n+62\left(n-1\right)\ ,\ n>1$$, where $$a_1=5$$

For n = 2, $$a_2=5\times\ 2+62\times\ 1\ =\ 72$$

For n = 3, $$a_3=72\times\ 4+62\times\ 2\ =\ 412$$

For n = 4, $$a_4=412\times\ 6+62\times\ 3=\ 2658$$

For n = 5, $$a_5=2658\times\ 8+62\times\ 4\ =\ 21512$$

Thus the correct option is C.

Since the question is only considering the 4th and 2nd lines,

Let us consider the third line of the illustration and arrange the 4th and 2nd lines accordingly.

III. Environment time and varies with mood man’s

Let Environment - 1, time - 2, and - 3, varies - 4, with - 5, mood - 6, and man's - 7.

Now, the coded version of III will be 1234567.

From the illustration, the code IV will be 3412765 and II will be 3216745.

Now after applying a similar code pattern in Step IV of the asked question, step II will be

Everyone about aware beautiful their was friendship.

Thus, the correct answer is B.