IIFT 2008 Question Paper

The given conditions are:-

1. The film must be submitted to the National Film Development Corporation (NFDC) by 31.10.2007.
2. The production cost of the film should not exceed Rupees Five crores.
3. The director of the film should have passed a three year course either from the Film and Television Institute of India (FTII) or from Satyajit Ray Film & Television Institute.
4. The length of the film should not exceed 150 minutes.
5. The film must have been approved by the film censor board of India.
We are given that:-

Film Dainandini was produced at the cost of Rupees 2.5 crore(thus fulfills 2). It was submitted to the NFDC on 29th September 2007(thus, fulfills 1). The director of the film Govind Chadha passed a 3-year course from FTII(thus fulfills 3). Length of film was 120 minutes(thus fulfills 4) and has been approved by the censor board of India(thus fulfills 5)
Hence, as the given film fulfills all the conditions it has to be selected.
Hence, option A is the correct answer.

The given conditions are:-

1. The film must be submitted to the National Film Development Corporation (NFDC) by 31.10.2007.
2. The production cost of the film should not exceed Rupees Five crores.
3. The director of the film should have passed a three year course either from the Film and Television Institute of India (FTII) or from Satyajit
Ray Film & Television Institute.
4. The length of the film should not exceed 150 minutes.
5. The film must have been approved by the film censor board of India.
We are told that,

Bhadrasalam is a 135-minute film directed(thus fulfills 4) by Katyani, who was a student of Satyajit Ray Film & Television Institute from 1996 to 1999(3 may or not be fulfilled). The cost of producing the film was Rupees 2.3 crore(thus, 2 is fulfilled) and it was submitted to NFDC on 24th July 2007(thus, fulfilling 1). The film has been approved by the censor board of India(thus it fulfills 5).
Thus, as we are not sure about 3, we cannot make any decision.
Hence, option B is the correct answer.

The first condition is:-
The film must be submitted to the National Film Development Corporation (NFDC) by 31.10.2007
The given film was approved by the censor board of India and submitted to NFDC on 30th Nov. 2007.
Thus, the given film does not fulfill condition 1 and as there is no alternative to condition 1, thus, the given film should not be selected.
Hence, option D is the correct answer.

The machine is arranging the numbers in the increasing order of the sum of the digits on the number.

Input: 245 (11), 316 (10), 436 (13), 519 (15), 868 (22), 710 (8), 689 (23).

The number in the bracket indicates the sum of digits of the given number.

Step 1: 710 (8), 316 (10), 436 (13), 519 (15), 868 (22), 245 (11), 689 (23).

∴ The machine has swapped 710 (8) with 245 (11).

Step 2: 710 (8), 316 (10), 245 (11), 519 (15), 868 (22), 436 (13), 689 (23).

Thus it has swapped 436 (13) with 245 (11).

Step 3: 710 (8), 316 (10), 245 (11), 436 (13), 868 (22), 519 (15), 689 (23).

Thus it has swapped 436 (13) with 519 (15).

Step 4: 710 (8), 316 (10), 245 (11), 436 (13), 519 (15), 868 (22), 689 (23).

Thus it has swapped 519 (15) with 868 (22).

Going by the logic mentioned above,

Input: 655 (16), 436 (13), 764 (17), 799 (25), 977 (23), 572 (14), 333 (9).

Step 1: 333 (9), 436 (13), 764 (17), 799 (25), 977 (23), 572 (14), 655 (16).

Step 2: 333 (9), 436 (13), 572 (14), 799 (25), 977 (23), 764 (17), 655 (16).

Step 3: 333 (9), 436 (13), 572 (14), 655 (16), 977 (23), 764 (17), 799 (25).

This is the required sequence which is achieved in Step 3.

Hence, option A is the correct answer. 

The machine arranges the numbers in the increasing order of the sum of the digits on the number.

Input: 245 (11), 316 (10), 436 (13), 519 (15), 868 (22), 710 (8), 689 (23).

The number in the bracket indicates the sum of digits of the given number.

Step 1: 710 (8), 316 (10), 436 (13), 519 (15), 868 (22), 245 (11), 689 (23).

∴ The machine has swapped 710 (8) with 245 (11).

Step 2: 710 (8), 316 (10), 245 (11), 519 (15), 868 (22), 436 (13), 689 (23).

Thus it has swapped 436 (13) with 245 (11).

Step 3: 710 (8), 316 (10), 245 (11), 436 (13), 868 (22), 519 (15), 689 (23).

Thus it has swapped 436 (13) with 519 (15).

Step 4: 710 (8), 316 (10), 245 (11), 436 (13), 519 (15), 868 (22), 689 (23).

Thus it has swapped 519 (15) with 868 (22).

Given input: 544(14), 653(14), 325(10), 688(22), 461(11), 231(6), 857(20)

Step 1: 231, 653, 325, 688, 461, 544, 857

Step 2: 231, 325, 653, 688, 461, 544, 857

Step 3: 231, 325, 461, 688, 653, 544, 857

Step 4: 231, 325, 461, 544, 653, 688, 857

Step 5: 231, 325, 461, 544, 653, 857, 688

Thus, the correct option is B.

The machine is arranging the numbers in the increasing order of the sum of the digits on the number.

Input: 245 (11), 316 (10), 436 (13), 519 (15), 868 (22), 710 (8), 689 (23).

The number in the bracket indicates the sum of digits of the given number.

Step 1: 710 (8), 316 (10), 436 (13), 519 (15), 868 (22), 245 (11), 689 (23).

∴ The machine has swapped 710 (8) with 245 (11).

Step 2: 710 (8), 316 (10), 245 (11), 519 (15), 868 (22), 436 (13), 689 (23).

Thus it has swapped 436 (13) with 245 (11).

Step 3: 710 (8), 316 (10), 245 (11), 436 (13), 868 (22), 519 (15), 689 (23).

Thus it has swapped 436 (13) with 519 (15).

Step 4: 710 (8), 316 (10), 245 (11), 436 (13), 519 (15), 868 (22), 689 (23).

Thus it has swapped 519 (15) with 868 (22).

We are given the result obtained in step 3rd. We can't go backward as there is no logic for processing backward. Hence, option D is the correct answer.

The machine arranges the numbers in the increasing order of the sum of the digits on the number.

Input: 245 (11), 316 (10), 436 (13), 519 (15), 868 (22), 710 (8), 689 (23).

The number in the bracket indicates the sum of digits of the given number.

Step 1: 710 (8), 316 (10), 436 (13), 519 (15), 868 (22), 245 (11), 689 (23).

∴ The machine has swapped 710 (8) with 245 (11).

Step 2: 710 (8), 316 (10), 245 (11), 519 (15), 868 (22), 436 (13), 689 (23).

Thus it has swapped 436 (13) with 245 (11).

Step 3: 710 (8), 316 (10), 245 (11), 436 (13), 868 (22), 519 (15), 689 (23).

Thus it has swapped 436 (13) with 519 (15).

Step 4: 710 (8), 316 (10), 245 (11), 436 (13), 519 (15), 868 (22), 689 (23).

Thus it has swapped 519 (15) with 868 (22).

Given Input: 653(17), 963(18), 754(16), 345,(12) 364(13), 861(15), 541(10).

Step 1: 541, 963, 754, 345, 364, 861, 653

Step 2: 541, 345, 754, 963, 364, 861, 653

Step 3: 541, 345, 364, 963, 754, 861, 653

Thus, the correct option is C.

The arrangement is made by the last letter of each word.

The last letters of the seven words of the sample sequence input were e, s, d, n, g, t, and m.

In the final step, the words were arranged as t, s, n, m, g, d, and e, i.e., in descending order.

Now, the last letters of the seven words of the input in the questions are e, s, g, t, o, h, and r.

In the final step, the words will be arranged in the order of t, s, r, o, h, g, and e.

Option B represents the last step's accurate representation, and the correct option is B.

The arrangement is made by the last letter of each word.

The last letters of the seven words of the sample sequence input were e, s, d, n, g, t, and m.

In the final step, the words were arranged as t, s, n, m, g, d, and e, i.e., in descending order.

In each step, one letter was fixed in its last step position.

The last letters of the input are t, s, e, o, g, l, and n, and in the asked step, the letters are t, s, o, n, l, e, and g.

After the first step, the last letters of the pattern will be t, s, e, o, g, l, and n.

After the second step, the last letters of the pattern will be t, s, e, o, g, l, and n.

After the third step, the last letters of the pattern will be t, s, o, e, g, l, and n.

After the fourth step, the last letters of the pattern will be t, s, o, n, e, g, and l.

After the fifth step, the last letters of the pattern will be t, s, o, n, l, e, and g. Since this is the required pattern, the options do not give the correct answer.

Thus, the correct option is D.

The arrangement is made by the last letter of each word.

The last letters of the seven words of the sample sequence input were e, s, d, n, g, t, and m.

In the final step, the words were arranged as t, s, n, m, g, d, and e, i.e., in descending order.

In each step, one letter was fixed in its last step position.

In the given input, the last letters are r, s, o, k, n, e, and y.

The first step: y, r, s, o, k, n, and e.

The second step: y, s, r, o, k, n, and e.

The third step: y, s, r, o, n, k, and e.

Thus, the correct answer is 3 and the correct option is D.