IIFT 18th Dec 2022 Slot 1

From the given information, we get the following table.

In round 5, there is only one winner and one loser. Hence Smita & Atharv must play against each other.

In rounds 2,3 &4, there is one draw each. Hence those players must play against each other in their respective rounds.

From the above conclusions, we get the following table.

In round 1, Atharv cannot play against Cheena as both of them are winners. Hence, he plays against Sumedha in round 1 & against Cheena in round 4.

In round 4, only Smita & Parul are left. So they play against each other.

Then In round 3, Sumedha & Smita and Parul & Cheena will play against each other, respectively.

As Sumedha played against Smita in round 3, she will play against Cheena in round 2.

Then Isha plays against Smita in round 2.

Smita played against everyone except Cheena. Hence, she plays against Cheena in round 1.

Then Parul must have played against Isha in round 1.

Sumedha played against everyone except Parul. Hence she plays against Parul in round 5.

Cheena played against Isha in round 5.

Hence, The final arrangement is

1A) Cheena won in rounds 1 & 4. In those rounds, she played against Smita & Atharv.

Option (B) is correct.

From the given information, we get the following table.

In round 5, there is only one winner and one loser. Hence Smita & Atharv must play against each other.

In rounds 2,3 &4, there is one draw each. Hence those players must play against each other in their respective rounds.

From the above conclusions, we get the following table.

In round 1, Atharv cannot play against Cheena as both of them are winners. Hence, he plays against Sumedha in round 1 & against Cheena in round 4.

In round 4, only Smita & Parul are left. So they play against each other.

Then In round 3, Sumedha & Smita and Parul & Cheena will play against each other, respectively.

As Sumedha played against Smita in round 3, she will play against Cheena in round 2.

Then Isha plays against Smita in round 2.

Smita played against everyone except Cheena. Hence, she plays against Cheena in round 1.

Then Parul must have played against Isha in round 1.

Sumedha played against everyone except Parul. Hence she plays against Parul in round 5.

Cheena played against Isha in round 5.

Hence, The final arrangement is

The game between Smita & Parul played in round 4, i.e 9:45 AM.

Option (D) is correct.

From the given information, we get the following table.

In round 5, there is only one winner and one loser. Hence Smita & Atharv must play against each other.

In rounds 2,3 &4, there is one draw each. Hence those players must play against each other in their respective rounds.

From the above conclusions, we get the following table.

In round 1, Atharv cannot play against Cheena as both of them are winners. Hence, he plays against Sumedha in round 1 & against Cheena in round 4.

In round 4, only Smita & Parul are left. So they play against each other.

Then In round 3, Sumedha & Smita and Parul & Cheena will play against each other, respectively.

As Sumedha played against Smita in round 3, she will play against Cheena in round 2.

Then Isha plays against Smita in round 2.

Smita played against everyone except Cheena. Hence, she plays against Cheena in round 1.

Then Parul must have played against Isha in round 1.

Sumedha played against everyone except Parul. Hence she plays against Parul in round 5.

Cheena played against Isha in round 5.

Hence, The final arrangement is

Option (1) True. Parul won against Isha at 09:00 AM in round 1.

Option (2) True. Smita lost against Sumedha at 09:30 AM in round 3.

Option (3) False. Cheena won against Atharv at 09:45 AM in round 4.

Option (4) True. Atharv lost against Smita at 10:00 AM in round 5.

From the given information, we get the following table.

In round 5, there is only one winner and one loser. Hence Smita & Atharv must play against each other.

In rounds 2,3 &4, there is one draw each. Hence those players must play against each other in their respective rounds.

From the above conclusions, we get the following table.

In round 1, Atharv cannot play against Cheena as both of them are winners. Hence, he plays against Sumedha in round 1 & against Cheena in round 4.

In round 4, only Smita & Parul are left. So they play against each other.

Then In round 3, Sumedha & Smita and Parul & Cheena will play against each other, respectively.

As Sumedha played against Smita in round 3, she will play against Cheena in round 2.

Then Isha plays against Smita in round 2.

Smita played against everyone except Cheena. Hence, she plays against Cheena in round 1.

Then Parul must have played against Isha in round 1.

Sumedha played against everyone except Parul. Hence she plays against Parul in round 5.

Cheena played against Isha in round 5.

Hence, The final arrangement is

Smita played against Sumedha in round 3. Before round 3, Smita lost in rounds 1 & 2, i.e. 2 games.

Option (A) is the answer.

Out of A, B, C, D & E, three are developed countries, and two are developing countries.

a) Country A is a developed country.

b) It is given that no two developing countries will sit next to each other and country D will always be seated next to a developing country.

Hence country D is a developed country.

c) It is given in the question that 'C' is also a developed country. Hence 'B' and 'E' are developing countries.

Country A will always take a seat as far as possible from country B. Two arrangements are possible.

No two developing countries will sit next to each other. Hence, 'E' can take only one position.

Countries 'C' and 'D' can take either of the positions.

Option (A) is True.

Option (B) is True.

Option (C) is True.

Option (D) is False.

Hence Option (D) is the answer.

Out of A, B, C, D & E, three are developed countries, and two are developing countries.

a) Country A is a developed country.

b) The country A which is a developed country. will always take a seat a far as possible from country B

These are the two possible positions.

c) It is given that no two developing countries will sit next to each other and country D will always be seated next to a developing country.

Hence country D is a developed country.

It is given in the question that 'D' has a developing country to its right.

So, two  'B', 'C' and 'E' are developing countries.

Now, what can be the possible positions of D.

There are 4 possible positions for D.

Of these positions only at 3, 4 D has B to it right. So, The answer is 2.

Given A and B are as far as possible. And also E is sitting right to A. With this information there are 2 arrangements.

Now we have to arrange C, D in those two positions. 

From the given information,

1) Tom will sit on the left of Richard.

2) John and Jame will sit together.

3) Michael is not in extreme cabins.

4) John, Michael, Richard and Tom are readers.

5) Jame, Mary and Franka are non-readers.

6) Mary is in the third cabin, and as she doesn't like reading, on both sides of her cabin, non-readers must be seated.

It is given that Michael is not in extreme cabins. Hence he must take the fifth or sixth cabin.

Case (1):- Michael is in the sixth cabin.

In this configuration, Tom and Richard cannot sit together. Hence this case is not possible.

 Case (2):- Michael is in the fifth cabin.

Tom and Richard can take the sixth and seventh cabins only.

Since Jane and John have to sit together. Jane can only take the second cabin. Hence Franka will take the third cabin.

Therefore the farthest person from Mary is Richard.

Option (D) is correct.

From the given information,

1) Tom will sit on the left of Richard.

2) John and Jame will sit together.

3) Michael is not in extreme cabins.

4) John, Michael, Richard and Tom are readers.

5) Jame, Mary and Franka are non-readers.

6) Mary is in the third cabin, and as she doesn't like reading, on both sides of her cabin, non-readers must be seated.

It is given that Michael is not in extreme cabins. Hence he must take the fifth or sixth cabin.

Case (1):- Michael is in the sixth cabin.

In this configuration, Tom and Richard cannot sit together. Hence this case is not possible.

Case (2):- Michael is in the fifth cabin.

Tom and Richard can take the sixth and seventh cabins only.

Since Jane and John have to sit together. Jane can only take the second cabin. Hence Franka will take the third cabin.

Therefore Michael occupies the fifth cabin.

Option (C) is correct.

Let's name the 8 locations as L1, L2, L3, L4, L5, L6, L7, L8.

From each of the 8 locations, we will have a bus to all the other seven locations in the morning. So, there will be 8*7=56 buses scheduled in the morning.

Also, we will have the same number of buses scheduled in the evening. So, another 56 buses have to be scheduled.

The total number of buses is 56+56=112.