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Six friends - Parul, Sumedha, Smita, Cheena, Isha, and Atharv: are playing Coin-Flip game. The person who gets 'Head' wins the game and if both persons get /Head' or both get 'Tail' the game ends in a Draw. Each toss ended as a 'Win (W)' or a 'Loss (L)' or a Draw (D). The game started at 09:00 AM with three tosses between the six friends. The other time slot at which the toss was done was at 09:15 AM, 09:30 AM, 09:45 AM and 10:00 AM. At each time slot, three tosses were held with each person playing exactly one toss at each time slot. Each person plays ·with the other person only once.
The results of the game are given in the order in which each person played the Coin-Flip game (from left to right).
From the given information, we get the following table.
In round 5, there is only one winner and one loser. Hence Smita & Atharv must play against each other.
In rounds 2,3 &4, there is one draw each. Hence those players must play against each other in their respective rounds.
From the above conclusions, we get the following table.
In round 1, Atharv cannot play against Cheena as both of them are winners. Hence, he plays against Sumedha in round 1 & against Cheena in round 4.
In round 4, only Smita & Parul are left. So they play against each other.
Then In round 3, Sumedha & Smita and Parul & Cheena will play against each other, respectively.
As Sumedha played against Smita in round 3, she will play against Cheena in round 2.
Then Isha plays against Smita in round 2.
Smita played against everyone except Cheena. Hence, she plays against Cheena in round 1.
Then Parul must have played against Isha in round 1.
Sumedha played against everyone except Parul. Hence she plays against Parul in round 5.
Cheena played against Isha in round 5.
Hence, The final arrangement is
The game between Smita & Parul played in round 4, i.e 9:45 AM.
Option (D) is correct.
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