Akhilesh Kumar
CAT Preparation Community 10y ago
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Akhilesh Kumar
CAT Preparation Community 10y ago
Praneeth Madhunanthu 10y ago
To maximize the points earned, we have to maximize the number of items bought and minimize the number of points lost.
We can maximize the number of items bought by buying the item of the least cost, i.e., C, which is Rs 70.
If we buy 14 items of C, we are left with Rs 20, which will give a loss of 30000 points. Instead, if we buy 13 items of C and 1 item of B, then we spent all Rs 1000 and bought the highest number of items possible. So, we have to buy 14 items.
Sharbari Shau 10y ago
But this violated the condition for 1A there is 1C
Surbhi 10y ago
But we can further maximise the profit by the following consideration. As we know from the question that: for every item E we buy, we need to buy 2 items D and 1item of B, which makes the total cost as Rs 215 and the total items bought as 4 in this particular purchase . Now, if we buy 4 of item E along with the aforementioned items , we will spend Rs 860 and will get 16 items in return.Now, for the full expenditure of Rs 1000, if we further buy 2 items of C for Rs 140, all the money would be spent and we will get the maximum profit of 18000 points. So, why cant we solve this question by this method? If anybody can help then please do!!!
Akash Agarwal 8y ago
Aditi Lohumi 6y ago
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Neha Modi 3y ago
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