$$\dfrac{a}{x}+\dfrac{b}{y}=\dfrac{1}{z}$$ Such equations can be simplied as $$\left(x-az\right)\left(y-bz\right)=a.b.z^2$$
Further, we can factorise $$a.b.z^2$$ which are the possible values for $$\left(x-az\right)\left(y-bz\right)$$
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$$\dfrac{a}{x}+\dfrac{b}{y}=\dfrac{1}{z}$$ Such equations can be simplied as $$\left(x-az\right)\left(y-bz\right)=a.b.z^2$$
Further, we can factorise $$a.b.z^2$$ which are the possible values for $$\left(x-az\right)\left(y-bz\right)$$
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