[Download PDF] AP ICET 2017 Question Paper Paper with Solutions

Instructions

For the following questions answer them individually

AP ICET 2017 - Question 131

If the coefficients of $$x^7$$ and $$x^8$$ are equal in the binomial expansion of $$(3 + \frac{x}{2})^n$$ then $$n =$$

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AP ICET 2017 - Question 132

If $$\alpha$$ is an integer, $$A = \begin{bmatrix}\alpha^2 & 5 \\5 & -\alpha \end{bmatrix}$$ and $$\mid A \mid^{10} = 1024$$ then $$\alpha =$$

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AP ICET 2017 - Question 133

$$A_x = \begin{bmatrix}\sin x & -\cos x \\\cos x & \sin x \end{bmatrix} \Rightarrow \sin x.A_x + \cos x.A_{\left(\frac{\pi}{2} + x\right)} =$$

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AP ICET 2017 - Question 134

$$\lim_{x \rightarrow a}\frac{(\sqrt{3x - a} - \sqrt{(x + a)})}{(x - a)} =$$

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AP ICET 2017 - Question 135

$$y = \cot^{-1}\left(\frac{1 - 3x^2}{3x - x^3}\right) \Rightarrow \frac{dy}{dx} =$$

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AP ICET 2017 - Question 136

The hypotenuse (in cms) of a right angle triangle whosesides are in the ratio 3:4 and having area 24 sq.cmsis

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Solution

Let the two sides be 3x and 4x. By Pythagoras' theorem, we get hypotenuse as 5x.
Now, Area of triangle = 0.5*3x*4x = 6x*x = 24 sq cm
Hence, x = 2 and thus, hypotenuse = 10 cm

AP ICET 2017 - Question 137

If the two diagonals of a parallelogram are equal and perpendicular bisectors of each other then it is a

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Solution

The diagonals of a parallelogram can be equal only if it is a square or rectangle.
The diagonals of a parallelogram can be perpendicular bisectors of each only if it is a square or a rhombus.
The only common feature in both the conditions is a squre.
Hence, the answer.

AP ICET 2017 - Question 138

If O is the center of a circle on which A, B and C are three points; and if $$\angle BOC = 100^\circ$$ then $$\angle ABC + \angle ACB =$$

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Solution

For ease of determination, make A and B ends of a diameter of a circle. This makes triangle ACB a right angled triangle and hence angle ACB becomes = 90 degrees.

Now, in isosceles triangle BOC, OB = OC (radii of same circle) and angle BOC = 100 degrees.
Hence, angles OBC and OCB = 40 degrees each. Hence, this also makes angle ABC = 40 degrees.

Hence, sum of the two required angles = 90+40 = 130 degrees.

AP ICET 2017 - Question 139

The triangle with vertices at (0, 0), (2, 2) and (0, 4) is

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Solution

If you plot the points roughly on a graph and drop a perpendicular from (2,2) on the side joining (0,0) and (0,4), it can be seen that the point (2,2) lies equidistant from the other two vertices.

Also, Pythagoras' theorem gets satisfied for the given triangles.
Hence, the triangle is an isosceles right angled triangle.

AP ICET 2017 - Question 140

If $$(\alpha, \beta)$$ and $$(\gamma, \delta)$$ are respectively the points which divide the line joining(7, -5) and (-2, 6) in the ratios 1 : 2 and 2 : 1 then $$\alpha + \gamma - \beta - \delta =$$

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CAT Content

AP ICET 2017 Question Paper

AP ICET 2017 Question Paper

AP ICET 2017 - Question 131

AP ICET 2017 - Question 132

AP ICET 2017 - Question 133

AP ICET 2017 - Question 134

AP ICET 2017 - Question 135

AP ICET 2017 - Question 136

AP ICET 2017 - Question 137

AP ICET 2017 - Question 138

AP ICET 2017 - Question 139

AP ICET 2017 - Question 140

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