Hi Swaroop,

The NMAT cut-off last year was 207. A safe score for a call would be around 213. If you can tell us more about which areas you are facing difficulty with, we will be able to pin-point specific things that you have to work on to improve your score and clear the cut-off. In any case, speed is an important factor in NMAT. Try to work on your speed. This will increase your number of attempts. Also, analyse the mocks to check where you are going wrong. If you find that you are weak in certain areas, work on those areas to answer questions in the next mock. Do let us know your weak areas so that we will be able to guide you better.

i score 45 in english weak in vocab barely score 2-3 answers correct out of 10 and grammar i leave rcs in nmat because it take too much time and unable to solve implicit questions in logical reasoning part, i have no idea about these questions..in quant sometimes i score 90+ , 70-75 and sometimes 50 based on difficulty level..

After the tank is tilted, the volume of empty space in the tank equals 1/2*60*60*40 = 72 litres.
This includes 32 litres of water which was collected.
So, the volume of the empty space before was 40 litres.
Hence, the height of the empty space was 40*1000/(40*60) = 16.66 cm
Hence, the height of water originally was 80-16.66 = 63.33 cm

Answer is c

@Maruti Sir, how u got 1/2*60*60*40? Can you please explain.

Hi Chandan,

Questions in ratio, proportion and percentages are quite commonly asked in competitive examinations. The single most important trick in solving these kind of questions is to ensure that you get the denominator correct while solving it.

For example, the percentage of profit will differ based on whether it is calculated on cost price or on selling price. It is important for a student to keep in mind these kind of differences to ensure that silly mistakes are not committed while solving questions.

The other important concept in ratio and proportion is the rule of Alligation.

Whenever a problem on profit loss is given, identify the data regarding cost price, selling price, marked price, discount and profit/loss quickly. If the data of any of the above terms is not given, then try to find its value using the information of the other terms. Have these 4 formulae on your tips and practice a lot:
1) Profit/Loss = Selling Price - Cost Price
2) Profit/Loss % = $$\frac{Profit/Loss}{Cost Price} * 100$$
3) Marked Price - Discount = Selling Price
4) Selling Price = Marked Price ($$1-\frac{Discount}{100}$$)

You can visit the cheat-sheet here to increase speed in calculations, especially in DI problems.
Approximation techniques: https://cracku.in/cat/quant-and-di/data-interpretation/cheatsheet

Hi like vikas said our DI CHEAT SHEET or FORMULA SHEET will help you in that

Value of car after 1st year, 2nd year and 3rd year will be Rs 900, Rs 810 and Rs 729 respectively.
Value of bike after 1st year, 2nd year and 3rd year will be respectively Rs 760, Rs 722 and Rs 685.9 respectively.
So Shyam pays Rs 43.1 to Ram.

options are
1.Ram paid Shyam Rs.80
2.Ram paid Shyam Rs.60
3. Shyam paid Ram Rs.80
4. Shyam paid Ram Rs.60

Hi Sachin,
If you are referring to seating arrangement around a circular table, read this concept which explains it:
https://cracku.in/banking/concept/seating-arrangement

Hi Arjun,

We hope that your preparation for IBPS PO Prelims is going on well. Do note that the exam will be conducted from October 2 and the results will be out in mid October. The paper consists of 100 questions (35 in Quant, 35 in Reasoning and 30 in English) and the time allotted is one hour. In this regard, all three subjects are equally important.

The IBPS PO Mains exams will be held on October 31 and is only for students who have cleared the preliminary examination. This examination will include General Awareness and Computer Knowledge in addition to the Prelims portion. We hope your question has been clarified. Do let us know if we can help you in anyway.

Regards,
Maruti

2700 = $$2^2 * 3^3 * 5^2$$ = 1*2*2*3*3*3*5*5
These are 8 numbers (not distinct). If we combine any two of them, the number becomes less than 8.
So, the number of ways of writing 2700 as a product of 8 distinct integers is 0.

And would be 6 as we can also take into account the negative numbers.

(x+y)(x-y) = 225

225 = 3^2 * 5^2

Number of factors = 3*3 = 9 = 225*1, 45*5, 25*9, 75*3, 15*15

x+y = 225 , x-y = 1 -> 1 solution pair. Similarly x+y = 1, x-y = 225 -> 1 solution pair

15*15 gives only 1 solution pair

Total number of pairs = 4*2 + 1 = 9