During the RRB exam, questions from various sections appear randomly and the test is not split into sections with individual time limits. Hence it is very unlikely that they will have sectional cutoffs. GK is a very important subject and upto 40% of the questions are based on it. So, candidates have to prepare well for to answer questions on general awareness.
There is a heavy penalty for wrong answers with -1/3 for every wrong answer. So, it is important that candidates don't guess the answers without enough effort. Around 1 crore candidates have applied for RRB exam this year and there are 18,000 vacancies. So, we estimate that the overall cutoff can be around 50 marks after including the negative marks as well.

I think the IBPS SO exam is over now. so it will next cm after 3-4 months...btw the age is for SO is 21 yrs minimum,,from the date of the application issue.

Overall

its overall ctf..........nt only in raiway bt also in SSC is well

Hi Divya, the solutions will be available on Friday

Hi Sunny, yes the Cracku app has English and Reasoning sections as well. In the Banking section, you will find the tile for Study Room. Once you go to Study Room, you can find the Quant, English and Reasoning sections.

The number is of the form 11k+7
The number cannot be a two digit number because maximum sum of the digits in a two digit number is 18
The minimum 3 digit number whose sum of digits is 23 is 599. The next number is 689, which is of the form 11k+7
689 mod 33 = 29

3+3+3+1 -> 4 ways
3+3+2+2 -> 6 ways
3+3+2+1+1 -> 30 ways
3+3+1+1+1+1 -> 15 ways
3+2+2+2+1 ->20 ways
3+2+2+1+1+1 -> 60 ways
3+2+1+1+1+1+1 -> 42 ways
2+2+2+2+2 -> 1 way
2+2+2+2+1+1 -> 15 ways
2+2+2+1+1+1+1 -> 35 ways
2+2+1+1+1+1+1+1 -> 28 ways
2+1+1+1+1+1+1+1+1 -> 9 ways
All 1s -> 1 way

Total number of ways = 266 ways

324.75

324.75

M - 1
I - 4
S - 4
P - 2

If letters can be repeated in a combination: Number of combinations = 2 * 5 * 5 * 3 - 1 (Each M can either be present or absent, similarly, each I can be present or absent and so on)
= 149

If letters should not be repeated: Number of combinations = $$^4C_1 + ^4C_2 + ^4C_3 + ^4C_4 = 2^4 - 1 = 15$$

16

16?