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Find the remainder when 12^107 is divided by 37? a)34 b)36 c)11 d)3
pls explain method u use to solve this...

Hi, This question is from cracku practice problem.

11433 and 13721 are divided by a certain number and the remainder is same in both cases then find the number of possible divisors?

Solution is ---

Required number of divisors are divisors of 13721 – 11433 = 2288 = 16*11*13
No. of divisors of 16*11*13 = (4+1)(1+1)(1+1)/2 = 10.

I am not getting why after calculating no of factors it is divided by 2. Should not the answer be 20?

cxcxcxc

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