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**how do i solve the reading comprehension**

**The remainders when 4864 and 5800 are divided by a certain number, X, are the same. What is the maximum possible number of divisors of X? In the explanation given - it says that X will be divisible by 5800-4864 Can someone explain how we can come up with this ?**

Hi Tanuj,

Let us prove why X is a factor of the difference of the numbers

let a,b,c be positive integers.

4864 = aX+c

5800 =bX+c

(b-a)X = 936

Maximum value X can have is 936 (i.e when (b-a) = 1).

Hence we calculate the divisors for 936.

Hope that helps.

Thanks,

Varun.

**Similar triangles are confusing me, specially the naming part, for instance, if it is given, triangles ABC and DEF are similar. If angle C is equal to angle E, AB is 4.2, DE is 2.1, BC is 6.4 and DF is 2.8 then find EF and AC. In the solution they have written AB/DE=BC/EF=AC/DF. But if angle C is equal to angle E then wont it be AB/DF? Since we take corresponding sides to equal angles,**

Hi Riya,

You are absolutely correct. If angle C = angle E, then the ratios will be AB/DE = BC/EF = AC/DF

Without having any context, I will be unable to comment further on this but the inference you are drawing is correct.

**A shopkeeper marks his good at 60% above the cost price. He allows a discount of 12 1/2%. Also he cheats 14 2/7% while purchasing and 20%at selling and gives one article free on purchase of 15 articles. Find the profit/loss in whole transaction.**

Hi Vikas

Let the cost price of 1 kg be 100. So the person marks the price as 160 and offers a discount of 20. Hence, He sells it for 140. However, he 1 + 1/7 = 8/7 kg for 100. Hence the effective cost price for him would be 100/(8/7) = 700/8.

Now he sells only 800 gm for 140. The cost price of 800 gm would be 700*.8/8 = 70.

Now he offers one article free for every 15. Hence his effective discount rate is 12.5 + 6.17 = 18.67

Hence his effective selling price is 160*8133 = 130.12.

Hence the required profit percentage = 60.12/70 = 85.88%

Hope that helps.

**how to solve jumbles**

Hi Tamil,

There are some systematic approaches to solving para jumbles.We have written a comprehensive blog on how to solve para jumbles.Please go through the link below to get the complete picture of para jumbles.

Blog link: https://cracku.in/blog/parajumbles-for-ibps-po/

Hope that helps.

Thanks,

Varun.

Hi,

We have an elaborate blog on the very same topic. Please refer the following link-

https://cracku.in/blog/para-jumbles-cat/

**how i improve verbal ??**

Hi

Can you please mention which topic you are weak at? This would enable us to help you in a better manner. Hope that helps.

**Fresh grapes have 75% water and the rest is pulp. During the process of drying, it was found that at a particular stage it contained 50% water by weight. What is the percentage reduction in the weight of the original quantity of fresh grapes?**

Hi,

Let's assume initially we had 200 gm of grapes. So, 50 gm is pulp and 150 gm is water. At some stage, water percentage was only 50% of the weight. This also means that the other 50% is pulp.

So, water got reduced to 50gm or 100gm reduction. Thus, percentage reduction is 66%.

**How many terms are there in the expression (1 + x2 + x4)10 when it is expanded?**

Hi,

The number of terms in a binomial expansion is given by

n+r-1C r-1

Here, n=10(power) and r=3(terms inside bracket)

So, number of terms = 12C2 = 66

**In how many ways can five integers be selected out of the first 30 natural numbers so that their product ends with five?**

Hi Arjun,

Implementing the following strategy can help you increase your accuracy in Reading Comprehension:

1. Identify the theme of every paragraph while reading the RC for the first time.

2. Identify the specific questions. These are questions that pertain to a specific paragraph in the essay. These questions can be answered with greater accuracy.

3. For the 'generic questions', try to eliminate the least likely options. As a general strategy, choose the RC whose topic is familiar to you.

Try to answer at least three of the four questions in the RC. You can practise RC questions at the following link: https://cracku.in/cat/quotient